A247015 Number of integers x smaller than n and that satisfy sigma(x)/x > sigma(n)/n where sigma is the sum of divisors.
0, 0, 1, 0, 3, 0, 5, 1, 4, 2, 9, 0, 11, 5, 6, 2, 15, 1, 17, 2, 10, 9, 21, 0, 16, 11, 15, 4, 27, 1, 29, 7, 19, 16, 22, 0, 35, 18, 24, 4, 39, 4, 41, 12, 16, 23, 45, 0, 35, 15, 32, 14, 51, 7, 37, 9, 36, 29, 57, 0, 59, 31, 24, 14, 45, 9, 65, 22, 44, 13, 69, 1, 71
Offset: 1
Keywords
Examples
a(2) = 0, since below 2 no x have sigma(x)/x greater than sigma(2)/2. a(3) = 1, since below 3 only sigma(2)/2 is greater than sigma(3)/3.
Links
- Amiram Eldar, Table of n, a(n) for n = 1..10000
Programs
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Mathematica
r[n_] := r[n] := DivisorSigma[1,n]/n; a[n_] := Module[{rn = r[n]}, Count[Range[n-1], ?(r[#] > rn &)]]; Array[a, 73] (* _Amiram Eldar, Jul 01 2019 *)
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PARI
lista(nn) = {v = vector(nn, n, sigma(n)/n); for (n=1, nn, nb = sum(i=1, n, v[i] > v[n]); print1(nb, ", "););}
Formula
a(n) = 0 if and only if n is superabundant (A004394).
a(p) = p - 2, for p prime.