A247224 G.f. A(x) satisfies: A(x) = B(x)*(A(x) - x*C(x)) where B(x) = A(x/B(x)) and C(x) = A(x*C(x)).
1, 1, 2, 6, 26, 149, 1024, 7965, 68192, 632724, 6294190, 66579501, 744194484, 8747497833, 107718981328, 1385436413289, 18563761993762, 258579817821799, 3737335096804136, 55957031888334621, 866632465992896412, 13865193902724224273, 228875892203793317404, 3893773927147402337094
Offset: 0
Keywords
Examples
G.f.: A(x) = 1 + x + 2*x^2 + 6*x^3 + 26*x^4 + 149*x^5 + 1024*x^6 +... Let B(x) = A(x/B(x)) and C(x) = A(x*C(x)), where B(x) and C(x) begin: B(x) = 1 + x + x^2 + 2*x^3 + 9*x^4 + 53*x^5 + 354*x^6 + 2651*x^7 + 21951*x^8 + 197666*x^9 + 1911091*x^10 + 19665622*x^11 + 214060860*x^12 +... C(x) = 1 + x + 3*x^2 + 13*x^3 + 71*x^4 + 460*x^5 + 3399*x^6 + 27867*x^7 + 248789*x^8 + 2388199*x^9 + 24432778*x^10 + 264682253*x^11 + 3021086129*x^12 +... then A(x) = B(x) * (A(x) - x*C(x)).
Links
- Vaclav Kotesovec, Table of n, a(n) for n = 0..300
Programs
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PARI
{a(n)=local(A=1);for(i=1,n,A=serreverse(x-x/A*serreverse(x/(A +x^2*O(x^n))))/x);polcoeff(A,n)} for(n=0,30,print1(a(n),", "))
Formula
G.f. A(x) satisfies:
(1) A(x) = Series_Reversion( x - Series_Reversion(x/A(x)) * x/A(x) )/x.
(2) A(x) = x/Series_Reversion( (x - Series_Reversion(x*A(x))) * A(x)/x ).
Given B(x) = A(x/B(x)) and C(x) = A(x*C(x)), then:
(3.a) A(x) = B(x*A(x)) and A(x) = C(x/A(x)),
(3.b) B(x) = x/Series_Reversion(x*A(x)),
(3.c) C(x) = Series_Reversion(x/A(x))/x,
(3.d) B(x) = A(x)/(A(x) - x*C(x)),
(3.e) C(x) = A(x)*(1 - 1/B(x))/x.
Comments