A248012 a(n)=p1^(p2^(p3^(p4^...)))... where p1

2, 3, 2, 5, 8, 7, 2, 3, 32, 11, 8, 13, 128, 243, 2, 17, 8, 19, 32, 2187, 2048, 23, 8, 5, 8192, 3, 128, 29, 14134776518227074636666380005943348126619871175004951664972849610340958208, 31, 2, 177147, 131072, 78125, 8, 37, 524288, 1594323, 32, 41

Offset: 2

Author

Talha Ali, Sep 29 2014

Keywords

• nonn

Examples

			To find a(14) we first find the distinct prime factors of 14 which are 2 and 7, which leads to a(14)=2^7=128.
To find a(8) we find 8's prime factors, 8=2*2*2, the distinct prime factor is 2 therefore a(8)=2.
30 has 3 distinct prime factors {2,3,5}, so a(30)=2^(3^5)=14134776518227074636666380005943348126619871175004951664972849610340958208.
		

Links

• Reinhard Zumkeller, Table of n, a(n) for n = 2..65, 65 = 2*3*11-1

Crossrefs

Cf. A027748.

Programs

Haskell

a248012 = foldr1 (^) . a027748_row  -- Reinhard Zumkeller, Sep 29 2014