A248057 Positions of 1,1 in the Thue-Morse sequence (A010060).
2, 8, 14, 22, 26, 32, 38, 42, 50, 56, 62, 70, 74, 82, 88, 94, 98, 104, 110, 118, 122, 128, 134, 138, 146, 152, 158, 162, 168, 174, 182, 186, 194, 200, 206, 214, 218, 224, 230, 234, 242, 248, 254, 262, 266, 274, 280, 286, 290, 296, 302, 310, 314, 322, 328
Offset: 1
Examples
Thue-Morse sequence: 0,1,1,0,1,0,0,1,1,0,0,1,0,1,1,..., so that a(1) = 2 and a(2) = 8.
Links
- Clark Kimberling, Table of n, a(n) for n = 1..1000
Programs
-
Mathematica
z = 400; u = Nest[Flatten[# /. {0 -> {0, 1}, 1 -> {1, 0}}] &, {0}, 9] (* A010060 *) v = Rest[u] t1 = Table[If[u[[n]] == 0 && v[[n]] == 0, 1, 0], {n, 1, z}]; t2 = Table[If[u[[n]] == 0 && v[[n]] == 1, 1, 0], {n, 1, z}]; t3 = Table[If[u[[n]] == 1 && v[[n]] == 0, 1, 0], {n, 1, z}]; t4 = Table[If[u[[n]] == 1 && v[[n]] == 1, 1, 0], {n, 1, z}]; Flatten[Position[t1, 1]] (* A248056 *) Flatten[Position[t2, 1]] (* A091855 *) Flatten[Position[t3, 1]] (* A091785 *) Flatten[Position[t4, 1]] (* A248057 *) SequencePosition[ThueMorse[Range[400]],{1,1}][[All,2]] (* Requires Mathematica version 10 or later *) (* Harvey P. Dale, May 16 2017 *)
-
PARI
t(n)=hammingweight(n)%2; for(n=1,500,if(t(n)==1&&t(n-1)==1,print1(n,", "))); \\ Joerg Arndt, Mar 12 2022
Formula
a(n) = 2*A091855(n) for n >= 1.
a(n) = A157971(n) + 1. - Amiram Eldar, Jun 16 2025
Comments