A248545 a(n+1) = a(n)^2 + 75.
0, 75, 5700, 32490075, 1055604973505700, 1114301860089969598947932490075, 1241668635399966182910364962424859894024949485439789973505700
Offset: 0
Keywords
Links
- A. V. Aho and N. J. A. Sloane, Some doubly exponential sequences, Fibonacci Quarterly, Vol. 11, No. 4 (1973), pp. 429-437.
- A. V. Aho and N. J. A. Sloane, Some doubly exponential sequences, Fibonacci Quarterly, Vol. 11, No. 4 (1973), pp. 429-437 (original plus references that F.Q. forgot to include - see last page!)
- Index entries for sequences of form a(n+1)=a(n)^2 + ...
Crossrefs
Cf. A003095.
Programs
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Mathematica
RecurrenceTable[{a[n+1]==a[n]^2+75,a[0]==0},a,{n,0,10}] NestList[#^2+75&,0,10] (* Harvey P. Dale, Jan 14 2016 *)
Formula
a(n) ~ c^(2^n), where c = 8.688980833378203252201919626948141475048572223268...
Comments