A252491 a(n) = (10^(n^2) - 1)/(10^n - 1).
1, 101, 1001001, 1000100010001, 100001000010000100001, 1000001000001000001000001000001, 1000000100000010000001000000100000010000001, 100000001000000010000000100000001000000010000000100000001, 1000000001000000001000000001000000001000000001000000001000000001
Offset: 1
Crossrefs
Cf. A128889 (for 2 instead of 10).
Programs
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Maple
seq((10^(n^2)-1)/(10^n-1), n=1..20); # Robert Israel, Jan 08 2015
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PARI
A252491(n)=(10^(n^2)-1)\(10^n-1)
Comments