A253894 a(1) = 1, for n > 1, a(n) = 1 + a(A253889(n)).

1, 2, 2, 3, 3, 3, 4, 3, 4, 5, 4, 5, 4, 4, 5, 5, 4, 4, 5, 5, 6, 6, 4, 6, 5, 5, 6, 5, 6, 6, 6, 5, 6, 6, 6, 7, 7, 5, 6, 7, 5, 7, 6, 6, 7, 6, 6, 6, 7, 5, 7, 7, 5, 7, 7, 6, 7, 6, 6, 7, 6, 7, 5, 7, 7, 7, 7, 5, 8, 8, 7, 7, 7, 6, 8, 8, 6, 7, 8, 7, 7, 8, 6, 8, 7, 7, 8, 6, 7, 8, 8, 7, 7, 7, 6, 8, 8, 7, 8, 8, 7, 7, 7, 7, 7, 8, 8, 7, 8, 8, 8, 8, 6, 8, 8, 7, 8, 8, 8, 8

Offset: 1

Author

Antti Karttunen, Jan 22 2015

Keywords

• nonn

Links

• Antti Karttunen, Table of n, a(n) for n = 1..8192

Crossrefs

One more than A253893.

Sum of A254044 and A254045.

Cf. A064216, A070939, A253889.

Formula

a(1) = 1, for n > 1, a(n) = 1 + a(A253889(n)).

a(n) = A070939(A064216(n)). [Binary width of terms of A064216.]

a(n) = A253893(n) + 1.

a(n) = A254044(n) + A254045(n).