A254405 a(n) = floor(b(n)), where b(n) = b(n-1)^(5/2), b(1) = 2.
2, 5, 76, 50535, 574095583180, 249724133031150566792019567784, 31163862905284344117664280692583318559734023853854503847082621442686494830
Offset: 1
Crossrefs
Cf. A254406.
Programs
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Mathematica
Floor[RecurrenceTable[{a[1]==2,a[n]==a[n-1]^(5/2)},a,{n,1,10}]] Table[Floor[2^((5/2)^(n-1))], {n, 1, 10}]
Formula
a(n) = floor(2^((5/2)^(n-1))).