cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A255231 The number of factorizations n = Product_i b_i^e_i, where all bases b_i are distinct, and all exponents e_i are distinct >=1.

Original entry on oeis.org

1, 1, 1, 2, 1, 1, 1, 2, 2, 1, 1, 2, 1, 1, 1, 4, 1, 2, 1, 2, 1, 1, 1, 3, 2, 1, 2, 2, 1, 1, 1, 5, 1, 1, 1, 4, 1, 1, 1, 3, 1, 1, 1, 2, 2, 1, 1, 5, 2, 2, 1, 2, 1, 3, 1, 3, 1, 1, 1, 2, 1, 1, 2, 7, 1, 1, 1, 2, 1, 1, 1, 6, 1, 1, 2, 2, 1, 1, 1, 5, 4, 1, 1, 2, 1, 1, 1, 3, 1, 2, 1, 2, 1, 1, 1, 6, 1, 2, 2, 4, 1, 1, 1, 3, 1, 1, 1, 6, 1, 1, 1, 5, 1, 1, 1, 2, 2, 1, 1, 3
Offset: 1

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Author

Saverio Picozzi, Feb 18 2015

Keywords

Comments

Not multiplicative: a(48) = a(2^4*3) = 5 <> a(2^4)*a(3) = 4*1 = 4. - R. J. Mathar, Nov 05 2016

Examples

			From _R. J. Mathar_, Nov 05 2016: (Start)
a(4)=2: 4^1 = 2^2.
a(8)=2: 8^1 = 2^3.
a(9)=2: 9^1 = 3^2.
a(12)=2: 12^1 = 2^2*3^1.
a(16)=4: 16^1 = 4^2 = 2^2*4^1 = 2^4.
a(18)=2: 18^1 = 2*3^2.
a(20)=2: 20^1 = 2^2*5^1.
a(24)=3: 24^1 = 2^2*6^1 = 2^3*3^1.
a(32)=5: 32^1 = 2^1*4^2 = 2^2*8^1 = 2^3*4^1 = 2^5.
a(36)=4: 36^1 = 6^2 = 3^2*4^1 = 2^2*9^1.
a(48)=5: 48^1 = 3^1*4^2 = 2^2*12^1 = 2^3*6^1 = 2^4*3^1.
a(60)=2 : 60^1 = 2^2*15^1.
a(64)=7: 64^1 = 8^2 = 4^3 = 2^2*16^1 = 2^3*8^1 = 2^4*4^1 = 2^6.
a(72)=6 : 72^1 = 3^2*8^1 = 2^1*6^2 = 2^2*18^1 = 2^3*9^1 = 2^3*3^2.
(End)
		

Crossrefs

Cf. A000688 (b_i not necessarily distinct).

Programs

  • Maple
    # Count solutions for products if n = dvs_i^exps(i) where i=1..pividx are fixed
    Apiv := proc(n,dvs,exps,pividx)
        local dvscnt, expscopy,i,a,expsrt,e ;
        dvscnt := nops(dvs) ;
        a := 0 ;
        if pividx > dvscnt then
            # have exhausted the exponent list: leave of the recursion
            # check that dvs_i^exps(i) is a representation
            if n = mul( op(i,dvs)^op(i,exps),i=1..dvscnt) then
                # construct list of non-0 exponents
                expsrt := [];
                for i from 1 to dvscnt do
                    if op(i,exps) > 0 then
                        expsrt := [op(expsrt),op(i,exps)] ;
                    end if;
                end do;
                # check that list is duplicate-free
                if nops(expsrt) = nops( convert(expsrt,set)) then
                    return 1;
                else
                    return 0;
                end if;
            else
                return 0 ;
            end if;
        end if;
        # need a local copy of the list to modify it
        expscopy := [] ;
        for i from 1 to nops(exps) do
            expscopy := [op(expscopy),op(i,exps)] ;
        end do:
        # loop over all exponents assigned to the next base in the list.
        for e from 0 do
            candf := op(pividx,dvs)^e ;
            if modp(n,candf) <> 0 then
                break;
            end if;
            # assign e to the local copy of exponents
            expscopy := subsop(pividx=e,expscopy) ;
            a := a+procname(n,dvs,expscopy,pividx+1) ;
        end do:
        return a;
    end proc:
    A255231 := proc(n)
        local dvs,dvscnt,exps ;
        if n = 1 then
            return 1;
        end if;
        # candidates for the bases are all divisors except 1
        dvs := convert(numtheory[divisors](n) minus {1},list) ;
        dvscnt := nops(dvs) ;
        # list of exponents starts at all-0 and is
        # increased recursively
        exps := [seq(0,e=1..dvscnt)] ;
        # take any subset of dvs for the bases, i.e. exponents 0 upwards
        Apiv(n,dvs,exps,1) ;
    end proc:
    seq(A255231(n),n=1..120) ; # R. J. Mathar, Nov 05 2016

Formula

a(n)=1 for all n in A005117. a(n)=2 for all n in A001248 and for all n in A054753 and for all n in A085987 and for all n in A030078. a(n)=3 for all n in A065036. a(n)=4 for all n in A085986 and for all n in A030514. a(n)=5 for all n in A178739, all n in A179644 and for all n in A050997. a(n)=6 for all n in A143610, all n in A162142 and all n in A178740. a(n)=7 for all n in A030516. a(n)=9 for all n in A189988 and all n in A189987. a(n)=10 for all n in A092759. a(n) = 11 for all n in A179664. a(n)=12 for all n in A179646. - R. J. Mathar, Nov 05 2016, May 20 2017

Extensions

Values corrected. Incorrect comments removed. - R. J. Mathar, Nov 05 2016