cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-3 of 3 results.

A255338 Each n occurs A255337(n) times.

Original entry on oeis.org

0, 1, 2, 3, 4, 4, 5, 6, 7, 7, 8, 8, 9, 9, 10, 11, 12, 13, 13, 14, 14, 14, 15, 15, 16, 16, 17, 17, 18, 18, 19, 20, 21, 22, 22, 23, 23, 23, 24, 24, 25, 25, 25, 26, 26, 26, 27, 27, 28, 29, 29, 30, 30, 30, 31, 31, 32, 32, 33, 33, 34, 34, 35, 36, 37, 38, 38, 39, 39, 39, 40, 40, 41, 41, 41, 42, 42
Offset: 0

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Author

Antti Karttunen, Feb 21 2015

Keywords

Crossrefs

The first differences gives A255339, the characteristic function of A255057.
Cf. A255337.

Formula

a(n) = The least k such that A255057(k) >= n.

A255057 The trunk of number-of-runs beanstalk, halved: a(n) = A255056(n)/2.

Original entry on oeis.org

0, 1, 2, 3, 5, 6, 7, 9, 11, 13, 14, 15, 16, 18, 21, 23, 25, 27, 29, 30, 31, 32, 34, 37, 39, 42, 45, 47, 48, 50, 53, 55, 57, 59, 61, 62, 63, 64, 66, 69, 71, 74, 76, 78, 81, 84, 87, 90, 93, 95, 96, 98, 101, 103, 106, 109, 111, 112, 114, 117, 119, 121, 123, 125, 126, 127
Offset: 0

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Author

Antti Karttunen, Feb 14 2015

Keywords

Crossrefs

First differences: A255337.
Characteristic function: A255339.

Formula

a(n) = A255056(n)/2.
a(n) = A255067(A255122(n)).

A255336 a(n) = A005811(A255056(n)); After the initial zero, the first differences of A255056.

Original entry on oeis.org

0, 2, 2, 2, 4, 2, 2, 4, 4, 4, 2, 2, 2, 4, 6, 4, 4, 4, 4, 2, 2, 2, 4, 6, 4, 6, 6, 4, 2, 4, 6, 4, 4, 4, 4, 2, 2, 2, 4, 6, 4, 6, 4, 4, 6, 6, 6, 6, 6, 4, 2, 4, 6, 4, 6, 6, 4, 2, 4, 6, 4, 4, 4, 4, 2, 2, 2, 4, 6, 4, 6, 4, 4, 6, 6, 6, 6, 4, 4, 6, 6, 6, 8, 6, 6, 6, 6, 6, 6, 4, 2, 4, 6, 4, 6, 4, 4, 6, 6, 6, 6, 6, 4, 2, 4, 6, 4, 6, 6, 4, 2, 4, 6, 4, 4, 4, 4, 2, 2
Offset: 0

Views

Author

Antti Karttunen, Feb 21 2015

Keywords

Comments

First differences of A255056, shifted once right (prepended with zero).

Crossrefs

First differences of A255056.
Terms of A255337 doubled.
Cf. A005811.
Analogous sequence: A213712.

Formula

a(n) = A005811(A255056(n)).
a(0) = 0; and for n >= 1: a(n) = A255056(n) - A255056(n-1).
a(n) = 2*A255337(n).
Showing 1-3 of 3 results.