A255405 a(n) = floor((2/sqrt(Pi))^n).
1, 1, 1, 1, 1, 2, 2, 2, 2, 3, 3, 4, 4, 5, 6, 6, 7, 8, 9, 11, 12, 14, 16, 18, 20, 23, 26, 29, 33, 37, 42, 47, 53, 60, 68, 77, 87, 98, 111, 125, 141, 159, 180, 203, 229, 258, 292, 329, 371, 419, 473, 534, 602, 680, 767, 865, 977, 1102, 1244, 1403, 1584, 1787, 2016, 2275, 2567
Offset: 0
Keywords
Links
- G. C. Greubel, Table of n, a(n) for n = 0..5000
- Kival Ngaokrajang, Illustration of initial terms.
- Wikipedia, Squaring the circle.
Programs
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Mathematica
Table[Floor[(2/Sqrt[Pi])^n], {n,0,50}] (* G. C. Greubel, Jan 09 2017 *)
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PARI
{for(n=1,100,a=floor(2^n/sqrt(Pi)^n);print1(a,", "))}
Formula
a(n) = floor((2/sqrt(Pi))^n).
Comments