A255482 a(n) = A064664(n)-A255479(n).

0, 0, 2, -1, 0, -1, 1, 2, -1, 1, -1, -2, 4, 2, -1, 1, 2, -2, -1, 0, 0, -4, 0, -4, -6, 5, 5, 1, 6, -5, 2, 4, 2, 3, -7, -7, 0, 0, 3, 6, -4, 0, 0, 2, -3, 1, -1, 1, -2, 0, 1, -1, -1, 1, -5, -1, -2, 7, -1, -3, -4, 3, -3, 0, -6

Offset: 1

Author

N. J. A. Sloane, Feb 28 2015

Keywords

• sign

Comments

Gives an idea of how similar A255582 is to A064413.

Links

• Ray Chandler, Table of n, a(n) for n = 1..10000

Crossrefs

Cf. A064413, A255582, A064664, A255479.

Programs

Haskell

a255482 n = a064664 n - a255479 n  -- Reinhard Zumkeller, Mar 10 2015