cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-3 of 3 results.

A257883 Sequence (a(n)) generated by Algorithm (in Comments) with a(1) = 0 and d(1) = 0.

Original entry on oeis.org

0, 1, 3, 2, 5, 9, 4, 10, 6, 11, 8, 15, 7, 16, 14, 22, 12, 23, 17, 27, 13, 25, 18, 31, 19, 33, 20, 35, 24, 40, 21, 38, 29, 47, 26, 45, 28, 48, 30, 51, 36, 58, 32, 55, 39, 63, 34, 59, 37, 64, 41, 67, 42, 70, 43, 72, 44, 74, 50, 81, 46, 78, 111, 49, 83, 52, 87
Offset: 1

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Author

Clark Kimberling, May 13 2015

Keywords

Comments

Algorithm: For k >= 1, let A(k) = {a(1), ..., a(k)} and D(k) = {d(1), ..., d(k)}. Begin with k = 1 and nonnegative integers a(1) and d(1). Let h be the least integer > -a(k) such that h is not in D(k) and a(k) + h is not in A(k). Let a(k+1) = a(k) + h and d(k+1) = h. Replace k by k+1 and repeat inductively.
Conjecture: if a(1) is a nonnegative integer and d(1) is an integer, then (a(n)) is a permutation of the nonnegative integers (if a(1) = 0) or a permutation of the positive integers (if a(1) > 0). Moreover, (d(n)) is a permutation of the integers if d(1) = 0, or of the nonzero integers if d(1) > 0.
Guide to related sequences:
a(1) d(1) (a(n)) (d(n))
0 0 A257883 A175499 except for initial terms
1 0 A175498 A175499 except for first term
2 1 A257910 A257909 except for initial terms

Examples

			a(1) = 0, d(1) = 0;
a(2) = 1, d(2) = 1;
a(3) = 3, d(3) = 2;
a(4) = 2, d(4) = -1.
		

Crossrefs

Programs

  • Mathematica
    a[1] = 0; d[1] = 0; k = 1; z = 10000; zz = 120;
    A[k_] := Table[a[i], {i, 1, k}]; diff[k_] := Table[d[i], {i, 1, k}];
    c[k_] := Complement[Range[-z, z], diff[k]];
    T[k_] := -a[k] + Complement[Range[z], A[k]]
    Table[{h = Min[Intersection[c[k], T[k]]], a[k + 1] = a[k] + h,
       d[k + 1] = h, k = k + 1}, {i, 1, zz}];
    u = Table[a[k], {k, 1, zz}]  (* A257883, = -1 + A175498 *)
    Table[d[k], {k, 1, zz}] (* A175499 except that here first term is 0 *)

Formula

a(k+1) - a(k) = d(k+1) for k >= 1.
Also, A257883(n) = -1 + A175498(n) for n >= 1.

A257905 Sequence (a(n)) generated by Rule 3 (in Comments) with a(1) = 0 and d(1) = 0.

Original entry on oeis.org

0, 1, 3, 2, 5, 11, 4, 9, 6, 13, 7, 15, 10, 8, 17, 35, 12, 25, 14, 29, 16, 33, 18, 37, 19, 39, 20, 41, 21, 43, 22, 45, 23, 47, 30, 26, 53, 24, 49, 40, 28, 57, 27, 55, 31, 63, 32, 65, 38, 42, 34, 69, 36, 73, 48, 97, 44, 89, 46, 93, 51, 103, 52, 105, 50, 101
Offset: 1

Views

Author

Clark Kimberling, May 16 2015

Keywords

Comments

Rule 3 follows. For k >= 1, let A(k) = {a(1), …, a(k)} and D(k) = {d(1), …, d(k)}. Begin with k = 1 and nonnegative integers a(1) and d(1).
Step 1: If there is an integer h such that 1 - a(k) < h < 0 and h is not in D(k) and a(k) + h is not in A(k), let d(k+1) be the least such h, let a(k+1) = a(k) + h, replace k by k + 1, and repeat Step 1; otherwise do Step 2.
Step 2: Let h be the least positive integer not in D(k) such that a(k) - h is not in A(k). Let a(k+1) = a(k) + h and d(k+1) = h. Replace k by k+1 and do Step 1.
Conjecture: suppose that a(1) is an nonnegative integer and d(1) is an integer.
If a(1) = 0 and d(1) != 1, then (a(n)) is a permutation of the nonnegative integers;
if a(1) = 0 and d(1) = 1, then (a(n)) is a permutation of the nonnegative integers excluding 1;
if a(1) = 1, then (a(n)) is a permutation of the positive integers;
if a(1) > 1, then (a(n)) is a permutation of the integers >1;
if d(1) = 0, then (d(n)) is a permutation of the integers;
if d(1) !=0, then (d(n)) is a permutation of the nonzero integers.
Guide to related sequences:
a(1) d(1) (a(n)) (d(n))

Examples

			a(1) = 0, d(1) = 0;
a(2) = 1, d(2) = 1;
a(3) = 3, d(3) = 2;
a(4) = 2, d(4) = -1.
		

Crossrefs

Cf. A256283 (putative inverse).

Programs

  • Haskell
    import Data.List ((\\))
    a257905 n = a257905_list !! (n-1)
    a257905_list = 0 : f [0] [0] where
       f xs@(x:_) ds = g [2 - x .. -1] where
         g [] = y : f (y:xs) (h:ds) where
                      y = x + h
                      (h:_) = [z | z <- [1..] \\ ds, x - z `notElem` xs]
         g (h:hs) | h `notElem` ds && y `notElem` xs = y : f (y:xs) (h:ds)
                  | otherwise = g hs
                  where y = x + h
    -- Reinhard Zumkeller, Jun 03 2015
  • Mathematica
    {a, f} = {{0}, {0}}; Do[tmp = {#, # - Last[a]} &[Min[Complement[#, Intersection[a, #]]&[Last[a] + Complement[#, Intersection[f, #]] &[Range[2 - Last[a], -1]]]]];
    If[! IntegerQ[tmp[[1]]], tmp = {Last[a] + #, #} &[NestWhile[# + 1 &, 1, ! (! MemberQ[f, #] && ! MemberQ[a, Last[a] - #]) &]]]; AppendTo[a, tmp[[1]]]; AppendTo[f, tmp[[2]]], {120}]; {a, f} (* Peter J. C. Moses, May 14 2015 *)

Formula

a(n) = A258046(n) - 1 for n >= 1.

A257909 Sequence (d(n)) generated by Rule 3 (in Comments) with a(1) = 0 and d(1) = 2.

Original entry on oeis.org

2, 1, 3, -2, 4, -3, 5, -1, 8, -10, 6, 12, -14, 10, -9, 11, -8, 14, -15, 13, -11, 15, -13, 17, -16, 18, -17, 19, -7, -6, -4, 21, -19, 23, -5, -12, 29, -31, 27, -22, 32, -29, 35, -37, 33, -27, 39, -41, 37, -34, 40, -36, 44, -45, 43, -39, 47, -49, 45, -42, 48
Offset: 1

Views

Author

Clark Kimberling, May 16 2015

Keywords

Comments

Rule 3 follows. For k >= 1, let A(k) = {a(1), …, a(k)} and D(k) = {d(1), …, d(k)}. Begin with k = 1 and nonnegative integers a(1) and d(1).
Step 1: If there is an integer h such that 1 - a(k) < h < 0 and h is not in D(k) and a(k) + h is not in A(k), let d(k+1) be the least such h, let a(k+1) = a(k) + h, replace k by k + 1, and repeat Step 1; otherwise do Step 2.
Step 2: Let h be the least positive integer not in D(k) such that a(k) - h is not in A(k). Let a(k+1) = a(k) + h and d(k+1) = h. Replace k by k+1 and do Step 1.
See A257905 for a guide to related sequences and conjectures.

Examples

			a(1) = 0, d(1) = 2;
a(2) = 1, d(2) = 1;
a(3) = 4, d(3) = 3;
a(4) = 2, d(4) = -2.
		

Crossrefs

Programs

  • Mathematica
    {a, f} = {{0}, {2}}; Do[tmp = {#, # - Last[a]} &[Min[Complement[#, Intersection[a, #]]&[Last[a] + Complement[#, Intersection[f, #]] &[Range[2 - Last[a], -1]]]]];
    If[! IntegerQ[tmp[[1]]], tmp = {Last[a] + #, #} &[NestWhile[# + 1 &, 1, ! (! MemberQ[f, #] && ! MemberQ[a, Last[a] - #]) &]]]; AppendTo[a, tmp[[1]]]; AppendTo[f, tmp[[2]]], {120}]; {a, f} (* Peter J. C. Moses, May 14 2015 *)
Showing 1-3 of 3 results.