cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A259124 If n is representable as x*y+x+y, with x>=y>1, then a(n) is the sum of all x's and y's in all such representations. Otherwise a(n)=0.

Original entry on oeis.org

0, 0, 0, 0, 0, 0, 0, 4, 0, 0, 5, 0, 0, 6, 6, 0, 7, 0, 7, 8, 0, 0, 17, 8, 0, 10, 9, 0, 20, 0, 10, 12, 0, 10, 34, 0, 0, 14, 23, 0, 26, 0, 13, 28, 0, 0, 43, 12, 13, 18, 15, 0, 32, 14, 29, 20, 0, 0, 67, 0, 0, 36, 32, 16, 38, 0, 19, 24, 32, 0, 76, 0, 0, 44, 21, 16, 44, 0, 57, 44
Offset: 1

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Author

Alex Ratushnyak, Jun 18 2015

Keywords

Comments

The sequence of numbers that never appear in a(n) begins: 1, 2, 3, 11, 27, 35, 51, 53, 79, 83, 89, 93, 117, 123, 125, 135, 143, 145.
The indices n at which a(n)=0 are in A254636. - Vincenzo Librandi, Jul 16 2015

Examples

			11 = 3*2 + 3 + 2, so a(11)=5.
		

Crossrefs

Programs

  • Maple
    f:= proc(n) local D,d;
          D:= select(t -> (t >= 3 and t^2 <= n+1), numtheory:-divisors(n+1));
          add(d + (n+1)/d - 2, d = D);
    end proc:
    map(f, [$1..100]); # Robert Israel, Aug 05 2015
  • Mathematica
    a[n_] := Sum[Boole[3 <= d <= Sqrt[n+1]] (d+(n+1)/d-2), {d, Divisors[n+1]}];
    Array[a, 100] (* Jean-François Alcover, Jun 08 2020, after Maple *)
  • PARI
    a(n)=sum(y=2,sqrtint(n+1)-1, my(x=(n-y)/(y+1)); if(denominator(x)==1, x+y)) \\ Charles R Greathouse IV, Jun 29 2015
  • Python
    TOP = 100
    a = [0]*TOP
    for y in range(2, TOP//2):
      for x in range(y, TOP//2):
        n = x*y + x + y
        if n>=TOP: break
        a[n] += x+y
    print(a[1:])
    
  • Python
    from sympy import divisors
    def A259124(n):
        m, c = n+1, 0
        for d in divisors(m):
            if d**2>m:
                break
            if d>=3:
                c += d+m//d-2
        return c # Chai Wah Wu, Oct 15 2024
    

Formula

a(n) = Sum({d: d | n+1 and 3 <= d <= sqrt(n+1)}, d + (n+1)/d - 2). - Robert Israel, Aug 05 2015