cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-5 of 5 results.

A260356 a(n) is the minimal value of Sum_{i=1..n} Product_{j=1..5} r_j(i), where each r_j is a permutation of {1,2,...,n}.

Original entry on oeis.org

1, 12, 60, 214, 600, 1443, 3089
Offset: 1

Views

Author

Chai Wah Wu, Jul 28 2015

Keywords

Comments

See Wu link for sets of permutations that achieve the value of a(n).

Crossrefs

Cf. A000292 (two permutations), A070735 (three permutations), A070736 (four permutations), A260357 (six permutations), A260358 (seven permutations), A260359 (eight permutations), A260355.

A260357 a(n) is the minimal value of Sum_{i=1..n} Product_{j=1..6} r_j(i), where each r_j is a permutation of {1,2,...,n}.

Original entry on oeis.org

1, 16, 108, 472, 1564, 4320
Offset: 1

Views

Author

Chai Wah Wu, Jul 28 2015

Keywords

Comments

See arXiv link for sets of permutations that achieve the value of a(n).

Crossrefs

Cf. A000292 (two permutations), A070735 (three permutations), A070736 (four permutations), A260356 (five permutations), A260358 (seven permutations), A260359 (eight permutations), A260355.

A260358 a(n) is the minimal value of Sum_{i=1..n} Product_{j=1..7} r_j(i), where each r_j is a permutation of {1,2,...,n}.

Original entry on oeis.org

1, 24, 198, 1043, 4074
Offset: 1

Views

Author

Chai Wah Wu, Jul 28 2015

Keywords

Comments

See arXiv link for sets of permutations that achieve the value of a(n).

Crossrefs

Cf. A000292 (two permutations), A070735 (three permutations), A070736 (four permutations), A260356 (five permutations), A260357 (six permutations), A260359 (eight permutations), A260355.

A260359 a(n) is the minimal value of Sum_{i=1..n} Product_{j=1..8} r_j(i), where each r_j is a permutation of {1,2,...,n}.

Original entry on oeis.org

1, 32, 360, 2304, 10618
Offset: 1

Views

Author

Chai Wah Wu, Jul 28 2015

Keywords

Comments

See arXiv link for sets of permutations that achieve the value of a(n).

Crossrefs

Cf. A000292 (two permutations), A070735 (three permutations), A070736 (four permutations), A260356 (five permutations), A260357 (six permutations), A260358 (seven permutations), A260355.

A331988 Table T(n,k) read by antidiagonals. T(n,k) is the maximum value of Product_{i=1..n} Sum_{j=1..k} r_j[i] where each r_j is a permutation of {1..n}.

Original entry on oeis.org

1, 2, 2, 6, 9, 3, 24, 64, 20, 4, 120, 625, 216, 36, 5, 720, 7776, 3136, 512, 56, 6, 5040, 117649, 59049, 10000, 1000, 81, 7, 40320, 2097152, 1331000, 248832, 24336, 1728, 110, 8, 362880, 43046721, 35831808, 7529536, 759375, 50625, 2744, 144, 9, 3628800, 1000000000, 1097199376, 268435456, 28652616, 1889568, 93636, 4096, 182, 10
Offset: 1

Views

Author

Chai Wah Wu, Feb 23 2020

Keywords

Comments

A dual sequence to A260355. See arXiv link for sets of permutations that achieve the value of T(n,k). The minimum value of Product_{i=1..n} Sum_{j=1..k} r_j[i] is equal to n!*k^n.

Examples

			T(n,k)
   k    1    2     3      4      5      6      7      8      9     10     11     12
  ---------------------------------------------------------------------------------
n  1|   1    2     3      4      5      6      7      8      9     10     11     12
   2|   2    9    20     36     56     81    110    144    182    225    272    324
   3|   6   64   216    512   1000   1728   2744   4096   5832   8000  10648  13824
   4|  24  625  3136  10000  24336  50625  93636 160000 256036 390625 571536 810000
		

Crossrefs

Programs

  • Python
    from itertools import permutations, combinations_with_replacement
    def A331988(n,k): # compute T(n,k)
        if k == 1:
            count = 1
            for i in range(1,n):
                count *= i+1
            return count
        ntuple, count = tuple(range(1,n+1)), 0
        for s in combinations_with_replacement(permutations(ntuple,n),k-2):
            t = list(ntuple)
            for d in s:
                for i in range(n):
                    t[i] += d[i]
            t.sort()
            w = 1
            for i in range(n):
                w *= (n-i)+t[i]
            if w > count:
                count = w
        return count

Formula

T(n,n) = (n*(n+1)/2)^n = A061718(n).
T(n,k) <= (k(n+1)/2)^n.
T(1,k) = k = A000027(k).
T(n,1) = n! = A000142(n).
T(2,2m) = 9m^2 = A016766(m).
T(2,2m+1) = (3m+1)*(3m+2) = A001504(m).
T(n,2) = (n+1)^n = A000169(n+1).
T(3,k) = 8k^3 = A016743(k) for k > 1.
If n divides k then T(n,k) = (k*(n+1)/2)^n.
If k is even then T(n,k) = (k*(n+1)/2)^n.
If n is odd and k >= n-1 then T(n,k) = (k*(n+1)/2)^n.
If n is even and k is odd such that k >= n-1, then T(n,k) = ((k^2*(n+1)^2-1)/4)^(n/2).
Showing 1-5 of 5 results.