A260384 Maximal gap between successive elements of Pn with n >= 3. Pn : primes p <= A002110(n) such that q=2*A002110(n)-p is prime. (p, q) is a pair of centered primes at n-th primorial.
6, 16, 44, 122, 268, 556, 886, 1446, 1964, 2900
Offset: 3
Examples
For n=3, primorial(3)=A002110(3) is 30 and P3 is (7, 13, 17, 19, 23, 29) because (53, 47, 43, 41, 37, 31) are all prime. The maximum gap between two consecutive terms of P3 is 6, obtained for (7,13) or (23,29), so a(3)=6.
Crossrefs
Cf. A002110.
Programs
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PARI
lstp(n)=my(v = []); pn = prod(i=1, n, prime(i)); forprime(p=1, pn-1, if (isprime(2*pn-p), v = concat(v, p))); my(w = vector(#v-1, k, v[k+1] - v[k])); vecmax(w); \\ Michel Marcus, Jul 24 2015
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PARI
a(n)=my(P=2*prod(i=1,n,prime(i)),r,last=P); forprime(p=2,P/2, if(isprime(P-p), r=max(r,p-last); last=p)); r \\ Charles R Greathouse IV, Jul 24 2015
Extensions
a(10) from Charles R Greathouse IV, Jul 24 2015
a(11) from Charles R Greathouse IV, Jul 28 2015
a(12) from Charles R Greathouse IV, Jul 30 2015