A260509 Number of graphs on labeled vertices {x, y, 1, 2, ..., n}, such that there is a partition of the vertices into V_1 and V_2 with x in V_1, y in V_2, every v in V_1 adjacent to an even number of vertices in V_2, and every v in V_2 adjacent to an even number of vertices in V_1.
1, 3, 23, 351, 11119, 703887, 89872847, 22945886799, 11740984910671, 12014755220129103, 24602393557227030863, 100754627840184914661711, 825349838279823049359417679, 13521969078301639826644261077327, 443083578482642171171990600910324047, 29037623349739387300519333731237743018319
Offset: 0
Keywords
Examples
a(2) = 23 because there are 23 graphs on {x, y, 1, 2} that admit a vertex partition separating x and y, such that each vertex in one half of the partition is adjacent to an even number of vertices in the other half. For instance, the graph with four edges (x,y), (x,1), (y,2), (1,2) admits the partition {{x,2},{y,1}}.
Links
- Caleb Stanford, Table of n, a(n) for n = 0..150
Crossrefs
Programs
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PARI
a(n) = sum(k=0, n, prod(i=1, k, 2^(i+1))*prod(i=k+1, n, 1 - 2^i)); \\ Michel Marcus, Sep 11 2015
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Python
# a_1(n) and a_2(n) both count the same sequence, in two different ways. def a_1(n) : # Output the number of 2-rooted graphs in (a) with n+2 vertices if n == 0 : return 1 else : return 2**((n*n + 3*n) // 2) - (2**n - 1) * a_1(n-1) def a_2(n) : # Output the number of 2-rooted graphs in (a) with n+2 vertices # Formula: \sum_{k=0}^n (\prod_{i=1}^k 2^{i+1}) (\prod_{i=k+1}^n (1 - 2^i)) curr_sum = 0 for k in range(0,n+1) : curr_prod = 1 for i in range(1,k+1) : curr_prod *= (2**(i+1)) for i in range(k+1,n+1) : curr_prod *= (1 - (2**i)) curr_sum += curr_prod return curr_sum
Formula
a(n) + (2^n - 1)*a(n-1) = 2^(binomial(n+2, 2) - 1) = 2^(n^3 + 3n).
a(n) = Sum_{k=0..n} (Product_{i=1..k} 2^(i+1))*(Product_{i=k+1..n} (1 - 2^i)).
Exponential generating function A(x) satisfies A(0) = 1 and A'(x) + 2A(2x) - A(x) = 4F(8x). Here F(x) is the exponential generating function counting the graphs on n labeled vertices, and satisfies F(0) = 1 and F'(x) = F(2x).
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