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This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A262313 Decimal expansion of the limit of the probability that a random binary word is an instance of the Zimin pattern "abacaba" as word length approaches infinity.

Original entry on oeis.org

1, 1, 9, 4, 4, 3, 6, 9, 5, 2, 5, 2, 8, 6, 3, 3, 7, 3, 0, 0, 0, 1, 1, 8, 5, 8, 6, 1, 2, 6, 8, 8, 5, 1, 0, 4, 8, 1, 5, 9, 0, 7, 9, 8, 8, 8, 1, 6, 8, 0, 8, 3, 3, 0, 8, 6, 3, 0, 6, 5, 2, 2, 2, 0, 2, 8, 9, 1, 4, 4, 5, 5, 9, 4, 2, 1, 0, 7, 7, 6, 1, 0, 7, 2
Offset: 0

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Author

Danny Rorabaugh, Sep 17 2015

Keywords

Comments

Word W over alphabet L is an instance of "abacaba" provided there exists a nonerasing monoid homomorphism f:{a,b,c}*->L* such that f(W)=abacaba. For example "01011010001011010" is an instance of "abacaba" via the homomorphism defined by f(a)=010, f(b)=11, f(c)=0. For a proof of the formula or more information on Zimin words, see Rorabaugh (2015).

Examples

			The constant is 0.11944369525286337300011858612688510481590798881680833086306522202891445594210776107239...
		

Crossrefs

Cf. A003000, A123121, A262312 (aba).

Formula

The constant is Sum_{n=1..infinity} A003000(n)*(Sum_{i=0..infinity} G_n(i)+H_n(i)), with:
G_n(i) = (-1)^i * r_n((1/2)^(2*2^i)) * (Product_{j=0..i-1} s_n((1/2)^(2*2^j))) / (Product_{k=0..i} 1-2*(1/2)^(2*2^k)),
r_n(x) = 2*x^(2n+1) - x^(4n) + x^(5n) - 2*x^(5n+1) + x^(6n),
s_n(x) = 1 - 2*x^(1-n) + x^(-n);
H_n(i) = (-1)^i * u_n((1/2)^(2*2^i)) * (Product_{j=0..i-1} v_n((1/2)^(2*2^j))) / (Product_{k=0..i} 1-2*(1/2)^(2*2^k)),
u_n(x) = 2*x^(4n+1) - x^(5n) + 2*x^(5n+1) + x^(6n),
v_n(x) = 1 - 2*x^(1-n) + x^(-n) - 2*x^(1-2n) + x^(-2n).
The inside sum is an alternating series and the outside sum has positive terms and a simple tail bound. Consequentially, we have the following bounds with any positive integers N and K:
Lower bound, Sum_{n=1..N} A003000(n)*(Sum_{i=0..2K-1} G_n(i)+H_n(i));
Upper bound, (1/2)^N + Sum_{n=1..N} A003000(n)*(Sum_{i=0..2K} G_n(i)+H_n(i)).