A262696 a(n)=0 if n is in A259934, otherwise number of terminal nodes (including n itself if it is a leaf) in that finite subtree whose root is n and whose edge-relation is defined by A049820(child) = parent.

0, 2, 0, 1, 1, 1, 0, 1, 1, 13, 1, 13, 0, 1, 1, 11, 1, 11, 0, 1, 1, 10, 0, 10, 1, 1, 1, 10, 1, 9, 0, 8, 1, 1, 0, 8, 1, 1, 6, 7, 1, 1, 0, 1, 1, 6, 0, 6, 5, 1, 1, 6, 1, 5, 0, 1, 1, 5, 0, 3, 4, 3, 0, 1, 1, 3, 1, 1, 1, 2, 0, 1, 4, 1, 1, 1, 7, 1, 0, 1, 1, 7, 1, 6, 4, 1, 1, 6, 1, 1, 0, 5, 1, 1, 0, 4, 4, 4, 1, 1, 1, 1, 0, 1, 3, 4, 0, 4, 1, 1, 1, 3, 1, 1, 0, 1, 1, 1, 0, 1, 3, 0, 4, 1

Offset: 0

Author

Antti Karttunen, Oct 04 2015

Keywords

• nonn

Examples

			For n=1, its transitive closure (as defined by edge-relation A049820(child) = parent) is the union of {1} itself together with all its descendants: {1, 3, 4, 5, 7, 8}. We see that there are no other nodes in a subtree whose root is 1, because A049820(3) = 3 - d(3) = 1, A049820(4) = 1, A049820(5) = 3, A049820(7) = 5, A049820(8) = 4 and of these only 7 and 8 are terms of A045765. Thus a(1) = 2.
For n=9, its transitive closure is {9, 11, 13, 15, 16, 17, 19, 21, 23, 24, 27, 29, 31, 33, 35, 36, 37, 39, 41, 43, 45, 47, 51, 53, 55, 57, 59, 61, 63, 64, 65, 67, 69, 71, 73, 75, 77, 79}, of which only thirteen members: {13, 19, 24, 33, 36, 37, 43, 55, 63, 64, 67, 75, 79} are leaves (in A045765), thus a(9) = 13.
		

Links

• Antti Karttunen, Table of n, a(n) for n = 0..17724

Crossrefs

Cf. A000005, A045765, A049820, A060990, A082284, A259934, A262686, A262693.

Cf. A262522, A262695, A262697.

Cf. also A213726.

Formula

If A262693(n) = 1 [when n is in A259934],

then a(n) = 0,

otherwise, if A060990(n) = 0 [when n is one of the leaves, A045765],

then a(n) = 1,

otherwise:

a(n) = Sum_{k = A082284(n) .. A262686(n)} [A049820(k) = n] * a(k).

(In the last clause [ ] stands for Iverson bracket, giving as its result 1 only when A049820(k) = n, and 0 otherwise).

Other identities:

For any n in A262511 but not in A259934, a(n) = a(A082284(n)).