A262713 Numbers k such that the sum of digits of k^2 is 10.
8, 19, 35, 46, 55, 71, 80, 145, 152, 179, 190, 251, 332, 350, 361, 449, 451, 460, 548, 550, 649, 710, 800, 1450, 1520, 1790, 1900, 2510, 3320, 3500, 3610, 4490, 4499, 4510, 4600, 5480, 5500, 6490, 7100, 8000, 14500, 15200, 17900, 19000, 20249, 20251, 24499
Offset: 1
Examples
19 is in sequence because 19^2 = 361 and 3+6+1 = 10.
Links
- Michael S. Branicky, Table of n, a(n) for n = 1..244
- Michael S. Branicky, Python program
Programs
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Magma
[n: n in [1..3*10^4] | &+Intseq(n^2) eq 10 ];
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Mathematica
Select[Range[10^5], Total[IntegerDigits[#^2]] == 10 &]
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PARI
for(n=1, 1e6, if (sumdigits(n^2) == 10, print1(n", "))) \\ Altug Alkan, Sep 28 2015
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Python
# See linked program to go to larger numbers def ok(n): return sum(map(int, str(n*n))) == 10 print(list(filter(ok, range(25000)))) # Michael S. Branicky, Aug 19 2021
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