A263088 a(n) = A262697(n^2).

0, 6, 2, 38, 2, 1, 1, 1, 1, 22, 1, 0, 0, 2, 1, 3, 1, 9, 1, 39, 1, 47, 1, 51, 4, 114, 1, 1, 1, 529, 2, 6, 2, 3, 1, 1, 22, 1, 11, 3, 2, 4, 7, 93, 7, 967, 1, 1, 3, 4, 1, 3, 2, 4, 1, 3, 1, 3, 1, 1, 1, 2, 1, 139, 2, 265, 2, 1, 6, 464, 12, 4, 22, 1, 2, 1503, 2, 6, 1, 5, 2, 2, 1, 2, 5, 1, 2, 4, 2, 1, 1, 6, 3, 386, 1, 1, 3, 800, 1, 2, 1, 7, 5, 1, 1, 3353, 1, 2, 21, 3, 1, 17, 3, 3, 1, 4, 1, 5, 1, 3, 9, 2

Offset: 0

Author

Antti Karttunen, Oct 12 2015

Keywords

• nonn

Comments

a(n)=0 if n^2 is in A259934, otherwise number of nodes in that finite subtree whose root is n^2 and edge-relation is defined by A049820(child) = parent. This count includes also leaves and n^2 itself.

Links

• Antti Karttunen, Table of n, a(n) for n = 0..222

Crossrefs

Cf. A000290, A049820, A259934, A262697.

Cf. also A261088, A263087.

Cf. A262515 (positions of zeros), A263093 (positions of ones).

Programs

Scheme

(define (A263088 n) (A262697 (A000290 n)))

Formula

a(n) = A262697(A000290(n)) = A262697(n^2).

Other identities. For all n >= 0:

If A263087(n) = 0, a(n) = 1.