A263458 Deal a pack of n cards into two piles and gather them up, n/2 times. All n such that this reverses the order of the deck.
4, 6, 12, 22, 28, 30, 36, 46, 52, 60, 70, 78, 100, 102, 108, 126, 148, 150, 156, 166, 172, 180, 190, 196, 198, 222, 228, 238, 262, 268, 270, 276, 292, 310, 316, 348, 358, 366, 372, 382, 388, 396, 420, 430, 438, 460, 462, 478, 486, 502, 508, 540, 556, 598
Offset: 1
Keywords
Examples
Take a deck of 52 playing cards. Deal it into two piles, then pick up the first pile and put it on top of the other. Do this 26 times. The order of the deck is reversed, so 52 belongs to this sequence. 6 is in the sequence because the 3 shuffles are [1, 2, 3, 4, 5, 6] -> [5, 3, 1, 6, 4, 2] -> [4, 1, 5, 2, 6, 3] -> [6, 5, 4, 3, 2, 1], original reversed. 8 is not in the sequence because the 4 shuffles are [1, 2, 3, 4, 5, 6, 7, 8] -> [7, 5, 3, 1, 8, 6, 4, 2] -> [4, 8, 3, 7, 2, 6, 1, 5] -> [1, 2, 3, 4, 5, 6, 7, 8] -> [7, 5, 3, 1, 8, 6, 4, 2], not the original reversed. - _R. J. Mathar_, Aug 02 2024
Programs
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Maple
isA263458 := proc(n) local L,itr ; L := [seq(i,i=1..n)] ; for itr from 1 to n/2 do L := pileShuf(L) ; # function code in A323712 end do: for i from 1 to nops(L) do if op(-i,L) <> i then return false ; end if; end do: true ; end proc: n := 1; for k from 2 do if isA263458(k) then printf("%d %d\n",n,k) ; n := n+1 ; end if; end do: # R. J. Mathar, Aug 02 2024
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Sage
from itertools import cycle def into_piles(r,deck): packs = [[] for i in range(r)] for card, pack in zip(range(1,deck+1),cycle(range(r))): packs[pack].insert(0,card) out = sum(packs,[]) return Permutation(out) def has_reversing_property(deck): p = power(into_piles(2,deck), deck/2) return p==into_piles(1,deck) [i for i in range(2,400,2) if has_reversing_property(i)]
Comments