A264907 a(n) is the smallest "cyclic" integer, k, that has exactly n prime factors.
1, 2, 15, 255, 5865, 146965, 3380195, 125067215, 7378965685, 494390700895, 36090521165335, 2571956263189313, 187752807212819849, 18212022299643525353, 1839414252263996060653, 196817324992247578489871, 21453088424154986055395939, 2981979290957543061700035521
Offset: 0
Keywords
Examples
The prime factorizations for terms a(1)..a(12) are: 2 3, 5 3, 5, 17 3, 5, 17, 23 5, 7, 13, 17, 19 5, 7, 13, 17, 19, 23 5, 7, 13, 17, 19, 23, 37 5, 7, 13, 17, 19, 23, 37, 59 5, 7, 13, 17, 19, 23, 37, 59, 67 5, 7, 13, 17, 19, 23, 37, 59, 67, 73 7, 11, 13, 17, 19, 31, 37, 41, 47, 59, 61 7, 11, 13, 17, 19, 31, 37, 41, 47, 59, 61, 73 Corrected by _Jeppe Stig Nielsen_, May 22 2021. 146965 = 5*7*13*17*19 is cyclic. Since it is the smallest example with 5 primes, 146965 = a(5). It is not a multiple of a(4) = 3*5*17*23. - _Jeppe Stig Nielsen_, May 22 2021
Programs
-
PARI
n=0;for(m=1,+oo,if(gcd(m,eulerphi(m))==1&&omega(m)==n,print1(m,", ");n++)) \\ slow, from Jeppe Stig Nielsen, May 22 2021
-
PARI
N=0;for(n=0,+oo,a=+oo;forsubset([N,n],x,m=prod(j=1,n,prime(x[j]));mJeppe Stig Nielsen, May 22 2021
Extensions
Wrong terms a(5), a(6), a(7), a(8), a(10), a(12) corrected, and more terms added, and a(0)=1 preprended by Jeppe Stig Nielsen, May 22 2021
a(17) from Jeppe Stig Nielsen, May 22 2021
Comments