cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A265248 Sum of the 2nd smallest parts of all the partitions of n (2nd smallest part is defined to be 0 when the partition does not have at least 2 distinct parts).

Original entry on oeis.org

0, 0, 2, 5, 14, 22, 43, 63, 97, 140, 201, 266, 371, 492, 638, 837, 1079, 1377, 1748, 2207, 2756, 3471, 4287, 5317, 6537, 8081, 9840, 12069, 14643, 17837, 21543, 26113, 31385, 37877, 45318, 54433, 64944, 77682, 92341, 109995, 130373, 154769, 182866, 216350, 254905, 300648, 353259, 415392, 486843, 570867
Offset: 1

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Author

Emeric Deutsch, Dec 24 2015

Keywords

Comments

a(n) = Sum_{k>=0} k*A265247(n,k).

Examples

			a(4) = 5 because in [4], [3,1], [2,2], [2,1,1], [1,1,1,1] the 2nd smallest parts are 0,3,0,2,0, respectively.
		

Crossrefs

Cf. A265247.

Programs

  • Maple
    g := add(x^i*add(j*x^j/mul(1-x^k, k = j .. 100), j = i+1 .. 100)/(1-x^i), i = 1 .. 100): gser := series(g, x = 0, 60): seq(coeff(gser, x, n), n = 1 .. 50);
    # second Maple program:
    b:= proc(n, i, t) option remember; `if`(n=0, [1, 0],
          `if`(i>n, 0, add((p-> `if`(t=1, p+[0, i*p[1]], p))(
           b(n-i*j, i+1, min(t+1,2))), j=1..n/i)+b(n, i+1, t)))
        end:
    a:= n-> b(n,1,0)[2]:
    seq(a(n), n=1..50);  # Alois P. Heinz, Dec 31 2015
  • Mathematica
    Table[Total@ Flatten@ Map[Take[DeleteDuplicates@ #, {-2}] &, Select[IntegerPartitions@ n, Total@ Differences@ # != 0 && Length@ # >= 2 &]], {n, 50}] (* Michael De Vlieger, Dec 24 2015 *)
    (* Second program: *)
    b[n_, i_, t_] := b[n, i, t] = If[n == 0, {1, 0},
         If[i > n, {0, 0}, Sum[If[t == 1, # + {0, i*#[[1]]}, #]&[
         b[n - i*j, i+1, Min[t+1, 2]]], {j, 1, n/i}] + b[n, i+1, t]]];
    a[n_] := b[n, 1, 0][[2]];
    Array[a, 50] (* Jean-François Alcover, Jun 05 2021, after Alois P. Heinz *)

Formula

G.f.: G(x) = Sum_{i>=1} x^i/(1-x^i)*Sum_{j>=i+1} j*x^j/Product_{k>=j}(1-x^k).
a(n) ~ exp(Pi*sqrt(2*n/3)) / (2*sqrt(3)*n). - Vaclav Kotesovec, Jun 12 2025