A268710 Number of iterations of A268395 needed to reach zero from 2^n + 1: a(n) = A268708(2^n + 1).

1, 2, 3, 4, 6, 9, 15, 25, 41, 75, 134, 246, 428, 802, 1454, 2643, 4588, 8851, 16849, 32368, 60504, 117343

Offset: 0

Author

Antti Karttunen, Feb 11 2016

Keywords

• nonn
• more

Crossrefs

Cf. A000051, A268395, A268708, A268709.

Programs

Scheme

(define (A268710 n) (A268708 (+ 1 (A000079 n))))

Formula

a(n) = A268708((2^n)+1).