A268827 Permutation of nonnegative integers: a(0) = 0, a(n) = A268717(1+A268825(n-1)).

0, 1, 3, 2, 6, 7, 5, 12, 4, 10, 14, 13, 15, 30, 26, 25, 27, 11, 9, 24, 8, 54, 50, 49, 51, 19, 17, 48, 16, 31, 29, 20, 28, 18, 22, 21, 23, 102, 98, 97, 99, 35, 33, 96, 32, 47, 45, 36, 44, 34, 38, 37, 39, 55, 53, 60, 52, 58, 62, 61, 63, 46, 42, 41, 43, 59, 57, 40, 56, 198, 194, 193, 195, 67, 65, 192, 64, 79, 77, 68, 76, 66, 70, 69, 71, 87

Offset: 0

Author

Antti Karttunen, Feb 14 2016

Keywords

• nonn

Comments

The "fifth shifted power" of permutation A268717.

Links

• Antti Karttunen, Table of n, a(n) for n = 0..8191
• Indranil Ghosh, C program to generate the sequence
• Index entries for sequences that are permutations of the natural numbers

Crossrefs

Inverse: A268828.

Cf. A268717, A268825, A268831.

Row 5 of array A268820.

Programs

Mathematica

A003188[n_]:=BitXor[n, Floor[n/2]]; A006068[n_]:=If[n<2, n, Block[{m = A006068[Floor[n/2]]}, 2m + Mod[Mod[n, 2] + Mod[m, 2], 2]]]; A268717[n_]:=If[n<1, 0, A003188[ 1 + A006068[n - 1]]]; A268823[n_]:= If[n<2, n, A268717[1 + A268717[1 + A268717[n - 2]]]]; A268825[n_]:=If[n<1, 0, A268717[1 + A268823[n - 1]]];  A268827[n_]:=If[n<1, 0, A268717[1 + A268825[n - 1]]]; Table[A268827[n], {n, 0, 100}] (* Indranil Ghosh, Apr 03 2017 *)

PARI

A003188(n) = bitxor(n, n\2);
A006068(n) = if(n<2, n, {my(m = A006068(n\2)); 2*m + (n%2 + m%2)%2});
A268717(n) = if(n<1, 0, A003188(1 + A006068(n - 1)));
A268823(n) = if(n<2, n, A268717(1 + A268717(1 + A268717(n - 2))));
A268825(n) = if(n<1, 0, A268717(1+A268823(n - 1)));
for(n=0, 100, print1(if(n<1, 0,  A268717(1+A268825(n - 1))),", ")) \\ Indranil Ghosh, Apr 03 2017

Python

def A003188(n): return n^(n//2)
def A006068(n):
    if n<2: return n
    else:
        m=A006068(n//2)
        return 2*m + (n%2 + m%2)%2
def A268717(n): return 0 if n<1 else A003188(1 + A006068(n - 1))
def A268823(n): return A268717(1 + A268717(1 + A268717(n - 2))) if n>1 else n
def A268825(n): return A268717(1 + A268823(n - 1)) if n>0 else 0
def a(n): return A268717(1 + A268825(n - 1)) if n>0 else 0
print([a(n) for n in range(101)]) # Indranil Ghosh, Apr 03 2017

Scheme

(define (A268827 n) (if (zero? n) n (A268717 (+ 1 (A268825 (- n 1))))))

Formula

a(0) = 0, for n >= 1, a(n) = A268717(1+A268825(n-1)).