A269422 Primes 8k + 3 at the end of the maximal gaps in A269420.
11, 43, 211, 419, 739, 1259, 1427, 4931, 15619, 22483, 43283, 83843, 273643, 373859, 1543811, 5364683, 5769403, 20942083, 137650523, 251523163, 369353099, 426009691, 938379811, 1042909163, 1378015843, 1878781763, 11474651731, 12402607739, 15931940483, 51025311059, 144309633179
Offset: 1
Keywords
Examples
The first two primes of the form 8k + 3 are 3 and 11, so a(1)=11. The next prime of this form is 19; the gap 19-11 is not a record so nothing is added to the sequence. The next prime of this form is 43 and the gap 43-19=24 is a new record, so a(2)=43.
Links
- Alexei Kourbatov and Marek Wolf, Predicting maximal gaps in sets of primes, arXiv preprint arXiv:1901.03785 [math.NT], 2019.
Programs
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PARI
re=0; s=3; forprime(p=11, 1e8, if(p%8!=3, next); g=p-s; if(g>re, re=g; print1(p", ")); s=p)
Comments