A273349 Triangle read by rows: T(n,k) is the number of bargraphs of semiperimeter n having k level steps (n>=2,k>=0). A level step in a bargraph is any pair of adjacent horizontal steps at the same height.
1, 1, 1, 3, 1, 1, 6, 5, 1, 1, 14, 12, 7, 1, 1, 33, 34, 19, 9, 1, 1, 79, 95, 61, 27, 11, 1, 1, 194, 261, 193, 95, 36, 13, 1, 1, 482, 728, 585, 333, 136, 46, 15, 1, 1, 1214, 2022, 1797, 1091, 521, 184, 57, 17, 1, 1, 3090, 5634, 5439, 3629, 1821, 763, 239, 69, 19, 1, 1
Offset: 2
Examples
Row 4 is 3,1,1 because the 5 (=A082582(4)) bargraphs of semiperimeter 4 correspond to the compositions [1,1,1], [1,2], [2,1], [2,2], [3] which, clearly, have 2,0,0,1,0 level steps. Triangle starts 1; 1,1; 3,1,1; 6,5,1,1; 14,12,7,1,1
References
- A. Blecher, C. Brennan, and A. Knopfmacher, Combinatorial parameters in bargraphs (preprint).
Links
- Alois P. Heinz, Rows n = 2..150, flattened
- M. Bousquet-Mélou and A. Rechnitzer, The site-perimeter of bargraphs, Adv. in Appl. Math. 31 (2003), 86-112.
Programs
-
Maple
G:=((1-t*z-z-2*z^2+t*z^2-sqrt((1-t*z-z-2*z^2+t*z^2)^2-4*z^3))*(1/2))/z: Gser:=simplify(series(G,z=0,21)): for n from 2 to 18 do P[n] := sort(coeff(Gser, z, n)) end do: for n from 2 to 18 do seq(coeff(P[n], t, j), j = 0 .. n-2) end do; # yields sequence in triangular form # second Maple program: b:= proc(n, y, t, w) option remember; expand( `if`(n=0, (1-t), `if`(t<0, 0, b(n-1, y+1, 1, 0))+ `if`(t>0 or y<2, 0, b(n, y-1, -1, 0))+ `if`(y<1, 0, `if`(w=1, z, 1)*b(n-1, y, 0, min(w+1, 1))))) end: T:= n-> (p-> seq(coeff(p, z, i), i=0..degree(p)))(b(n, 0$3)): seq(T(n), n=2..18); # Alois P. Heinz, Jun 04 2016
-
Mathematica
b[n_, y_, t_, w_] := b[n, y, t, w] = Expand[If[n == 0, 1 - t, If[t < 0, 0, b[n - 1, y + 1, 1, 0]] + If[t > 0 || y < 2, 0, b[n, y - 1, -1, 0]] + If[y < 1, 0, If[w == 1, z, 1]*b[n - 1, y, 0, Min[w + 1, 1]]]]]; T[n_] := Function [p, Table[Coefficient[p, z, i], {i, 0, Exponent[p, z]}]][ b[n, 0, 0, 0]]; Table[T[n], {n, 2, 18}] // Flatten (* Jean-François Alcover, Jul 29 2016, after Alois P. Heinz *)
Formula
G.f.: G(t,z) = (1-tz-z-2z^2+tz^2-sqrt((1-z)(1-z-2tz-4z^2+t^2z^2+2tz^2-4z^3-t^2z^3+4tz^3)))/(2z) (z marks semiperimeter, t marks level steps; obtained from the expression for F in the Blecher et al. reference (Section 7.1) by setting x=z, y=z, w=t).
Comments