A274098 Number of ways the most probable score sequence happens in an n-person round-robin tournament.
1, 2, 6, 24, 280, 8640, 233520, 23157120, 5329376640, 1314169920000, 1016970317932800, 1772428331094220800, 3441650619022551936000, 22088285526822118789785600, 291368298787833283829100288000
Offset: 1
Keywords
Examples
With 4 players there 6 = 4*3/2 games played with 2^(4*3/2) = 64 possible outcomes. The possible score sequences and the number of ways each can happen are as follows: 3210 24 (meaning one player won 3 times, one player won twice, one player won once, and one player had no wins, and this can happen in 24 ways) 3111 8 2220 8 2211 24 The most probable score sequence is either 3210 or 2211, and either can happen in 24 ways, so a(4)=24. (Usually there is a unique most probable score sequence.) The score sequences with 4 players are partitions of 6 into 4 parts. For 6 players the most probable score sequence is 4,3,3,2,2,1. It is unique, and happens in 8640 of the 2^15 possible outcomes, so a(6) = 8640.
References
- P. A. MacMahon, An American tournament treated by the calculus of symmetric functions, Quart. J. Pure Appl. Math., 49 (1920), 1-36. Gives a(1) to a(9).
Links
- Shalosh B. Ekhad, On the Most Commonly-Occurring Score Vectors for American Tournaments of n-players, and their Corresponding Records, published in the personal journal of Shalosh B. Ekhad and Doron Zeilberger, Jun 13 2016; Local copy, pdf file only, no active links
- P. A. MacMahon, An American tournament treated by the calculus of symmetric functions, Quart. J. Pure Appl. Math., 49 (1920), 1-36. Gives a(1) to a(9). [Annotated scanned copy, scanned at 300 dpi. Do not replace with a smaller file as the print is very tiny and hard to read.]
Crossrefs
Cf. A000571.
Extensions
a(1)-a(9) confirmed by N. J. A. Sloane, Jun 11 2016
a(10)-a(15) from Shalosh B. Ekhad, Jun 13 2016
Comments