A275727 a(0) = 0, for n >= 1, a(n) = A275736(n) + 2*a(A257684(n)).

0, 1, 2, 3, 2, 3, 4, 5, 6, 7, 6, 7, 4, 5, 6, 7, 6, 7, 4, 5, 6, 7, 6, 7, 8, 9, 10, 11, 10, 11, 12, 13, 14, 15, 14, 15, 12, 13, 14, 15, 14, 15, 12, 13, 14, 15, 14, 15, 8, 9, 10, 11, 10, 11, 12, 13, 14, 15, 14, 15, 12, 13, 14, 15, 14, 15, 12, 13, 14, 15, 14, 15, 8, 9, 10, 11, 10, 11, 12, 13, 14, 15, 14, 15, 12, 13, 14, 15

Offset: 0

Author

Antti Karttunen, Aug 09 2016

Keywords

• nonn
• base
• look

Comments

a(n) has ones in those positions of its base-2 representation where n has nonzero digits in its factorial base representation.

Examples

			For n=19, A007623(19) = 301, thus a(19) = 5 because A007088(5) = 101.
		

Links

• Antti Karttunen, Table of n, a(n) for n = 0..40320
• Index entries for sequences related to binary expansion of n
• Index entries for sequences related to factorial base representation

Crossrefs

Cf. A000120, A007088, A007623, A048675, A060130, A257684, A275733, A275736.

Cf. also A275728.

Formula

a(0) = 0, for n >= 1, a(n) = A275736(n) + 2*a(A257684(n)).

a(n) = A048675(A275733(n)).

Other identities and observations. For all n >= 0:

A000120(a(n)) = A060130(n).