A276582 Simple self-inverse permutation of natural numbers: after a(0)=0, list each block of A261224(n) numbers in reverse order, from A261222(n) to A261223(1+n).

0, 1, 3, 2, 5, 4, 8, 7, 6, 11, 10, 9, 14, 13, 12, 18, 17, 16, 15, 23, 22, 21, 20, 19, 28, 27, 26, 25, 24, 34, 33, 32, 31, 30, 29, 40, 39, 38, 37, 36, 35, 47, 46, 45, 44, 43, 42, 41, 54, 53, 52, 51, 50, 49, 48, 61, 60, 59, 58, 57, 56, 55, 69, 68, 67, 66, 65, 64, 63, 62, 77, 76, 75, 74, 73, 72, 71, 70, 86, 85, 84, 83, 82, 81, 80, 79, 78

Offset: 0

Author

Antti Karttunen, Sep 07 2016

Keywords

• nonn

Comments

Maps between A276583 and A276584.

Links

• Antti Karttunen, Table of n, a(n) for n = 0..9996
• Index entries for sequences that are permutations of the natural numbers

Crossrefs

Cf. A261222, A261223, A261224, A276581, A276583, A276584.

Programs

Scheme

(define (A276582 n) (if (zero? n) n (+ (- (A261223 (+ 1 (A276581 n))) n) (A261222 (A276581 n)))))

Formula

a(0)=0; for n >= 1, a(n) = (A261223(1+A276581(n))- n)+A261222(A276581(n)).