A276630 a(n) = number of prime signature permutations which can prohibit the appearance of terms in A026477 that are members of the same signature set (see explanation in "Comments" and "Examples").
0, 0, 0, 1, 1, 1, 1, 0, 1, 1, 1, 0, 1, 1, 1, 0, 1, 1, 1, 1, 1, 1, 1, 0, 1, 2, 1, 1, 2, 1, 1, 1, 1, 1, 2, 2, 2, 2, 1, 2, 2, 0, 1, 1, 0, 0, 0, 1, 1, 1, 1, 2, 2, 2, 1, 1, 1, 2, 3, 2, 2, 0, 1, 2, 2, 2, 2
Offset: 1
Keywords
Examples
NOTE: Partitions are in graded reverse lexicographic order. a(8) = 0; the 8th partition is {4}, therefore members of {4} (i.e., primes p^4) appear in A026477. a(14) = 1; the 14th partition is {4,1}. The one group of three previously-appearing members of signature sets in A026477 whose sums permute to {4,1} is {4} + {1} + {}, so members of {4,1} do not appear in A026477. Note that while {2} (p^2) also appears and {2} + {2} + {1} also permutes to {4,1}, it does not pertain here because {2} + {2} = {4} iff p^2*p^2 = p^4, violating the condition that all terms are products of distinct prior terms. So a(14) = 1, rather than 2. a(59) = 3; the 59th partition is {3,3,1,1}. The three applicable signature sets which permute to {3,3,1,1} are A: {1,1,1,1} + {2} + {2}; B: {3,1,1} + {2} + {1} and C: {3,3} + {1} + {1}; so members of {3,3,1,1} do not appear in A026477. Note that A and C pertain here with repeated signature sets ({2} for A and {1} for C) because, unlike a(14), their placement in the permutation is different. So for instance, {1,1,1,1} in A = primes p*q*r*s, so one {2} may = p^2 while the other {2} may = q^2.
Comments