A279391 Irregular triangle read by rows in which row n lists the subparts of the successive layers of the symmetric representation of sigma(n).
1, 3, 2, 2, 7, 3, 3, 11, 1, 4, 4, 15, 5, 3, 5, 9, 9, 6, 6, 23, 5, 7, 7, 12, 12, 8, 7, 8, 1, 31, 9, 9, 35, 2, 2, 10, 10, 39, 3, 11, 5, 5, 11, 18, 18, 12, 12, 47, 13, 13, 5, 13, 21, 21, 14, 6, 6, 14, 55, 1, 15, 15, 59, 3, 7, 3, 16, 16, 63, 17, 7, 7, 17, 27, 27, 18, 9, 18, 3, 71, 10, 10, 19, 19, 30, 30
Offset: 1
Examples
Triangle begins (first 15 rows): [1]; [3]; [2, 2]; [7]; [3, 3]; [11], [1]; [4, 4]; [15]; [5, 3, 5]; [9, 9]; [6, 6]; [23], [5]; [7, 7]; [12, 12]; [8, 7, 8], [1]; ... For n = 12 we have that the 11th row of triangle A237593 is [6, 3, 1, 1, 1, 1, 3, 6] and the 12th row of the same triangle is [7, 2, 2, 1, 1, 2, 2, 7], so the diagram of the symmetric representation of sigma(12) = 28 is constructed as shown below in Figure 1: . _ _ . | | | | . | | | | . | | | | . | | | | . | | | | . _ _ _| | _ _ _| | . _| _ _| _| _ _ _| . _| | _| _| | . | _| | _| _| . | _ _| | |_ _| . _ _ _ _ _ _| | 28 _ _ _ _ _ _| | 5 . |_ _ _ _ _ _ _| |_ _ _ _ _ _ _| . 23 . . Figure 1. The symmetric Figure 2. After the dissection . representation of sigma(12) of the symmetric representation . has only one part which of sigma(12) into layers of . contains 28 cells, so width 1 we can see two "subparts" . the 12th row of the that contain 23 and 5 cells . triangle A237270 is [28]. respectively, so the 12th row of . this triangle is [23], [5]. . For n = 15 we have that the 14th row of triangle A237593 is [8, 3, 1, 2, 2, 1, 3, 8] and the 15th row of the same triangle is [8, 3, 2, 1, 1, 1, 1, 2, 3, 8], so the diagram of the symmetric representation of sigma(15) = 24 is constructed as shown below in Figure 3: . _ _ . | | | | . | | | | . | | | | . | | | | . | | | | . | | | | . | | | | . _ _ _|_| _ _ _|_| . _ _| | 8 _ _| | 8 . | _| | _ _| . _| _| _| |_| . |_ _| 8 |_ _| 1 . | | 7 . _ _ _ _ _ _ _ _| _ _ _ _ _ _ _ _| . |_ _ _ _ _ _ _ _| |_ _ _ _ _ _ _ _| . 8 8 . . Figure 3. The symmetric Figure 4. After the dissection . representation of sigma(15) of the symmetric representation . has three parts of size 8 of sigma(15) into layers of . because every part contains width 1 we can see four "subparts". . 8 cells, so the 15th row of The first layer has three subparts: . triangle A237270 is [8, 8, 8]. 8, 7, 8. The second layer has . only one subpart of size 1, so . the 15th row of this triangle is . [8, 7, 8], [1]. . The smallest even number with 3 levels is 60; its row of subparts is: [119], [37], [6, 6]. The smallest odd number with 3 levels is 315; its row of subparts is: [158, 207, 158], [11, 26, 5, 9, 5, 26, 11], [4, 4]. - _Hartmut F. W. Hoft_, Sep 05 2021
Crossrefs
Programs
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Mathematica
(* support functions are defined in aA237593 and A262045 *) subP[level_] := Module[{s=Map[Apply[Plus, #]&, Select[level, First[#]!=0&]]}, If[OddQ[Length[s]], s[[(Length[s]+1)/2]]-=1]; s] a279391[n_] := Module[{widL=a262045[n], lenL=a237593[n], srs, subs}, srs=Transpose[Map[PadRight[If[widL[[#]]>0, Table[1, widL[[#]]], {0}], Max[widL]]&, Range[Length[lenL]]]]; subs=Map[SplitBy[lenL srs[[#]], #!=0&]&, Range[Max[widL]]]; Flatten[Map[subP, subs]]] Flatten[Map[a279391, Range[38]]] (* Hartmut F. W. Hoft, Sep 05 2021 *)
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