A280499 Triangular table for division in ring GF(2)[X]: T(n,k) = n/k, or 0 if k is not a divisor of n, where the binary expansion of each number defines the corresponding (0,1)-polynomial.
1, 2, 1, 3, 0, 1, 4, 2, 0, 1, 5, 0, 3, 0, 1, 6, 3, 2, 0, 0, 1, 7, 0, 0, 0, 0, 0, 1, 8, 4, 0, 2, 0, 0, 0, 1, 9, 0, 7, 0, 0, 0, 3, 0, 1, 10, 5, 6, 0, 2, 3, 0, 0, 0, 1, 11, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 12, 6, 4, 3, 0, 2, 0, 0, 0, 0, 0, 1, 13, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 14, 7, 0, 0, 0, 0, 2, 0, 0, 0, 0, 0, 0, 1, 15, 0, 5, 0, 3, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1
Offset: 1
Examples
The first 17 rows of the triangle: 1 2 1 3 0 1 4 2 0 1 5 0 3 0 1 6 3 2 0 0 1 7 0 0 0 0 0 1 8 4 0 2 0 0 0 1 9 0 7 0 0 0 3 0 1 10 5 6 0 2 3 0 0 0 1 11 0 0 0 0 0 0 0 0 0 1 12 6 4 3 0 2 0 0 0 0 0 1 13 0 0 0 0 0 0 0 0 0 0 0 1 14 7 0 0 0 0 2 0 0 0 0 0 0 1 15 0 5 0 3 0 0 0 0 0 0 0 0 0 1 16 8 0 4 0 0 0 2 0 0 0 0 0 0 0 1 17 0 15 0 5 0 0 0 0 0 0 0 0 0 3 0 1 ----------------------------------- 7 ("111" in binary) encodes polynomial X^2 + X + 1, which is irreducible over GF(2) (7 is in A014580), so it is divisible only by itself and 1, and thus T(7,1) = 7, T(7,k) = 0 for k=2..6 and T(7,7) = 1. 9 ("1001" in binary) encodes polynomial X^3 + 1, which is factored over GF(2) as (X+1)(X^2 + X + 1), and thus T(9,3) = 7 and T(9,7) = 3 because the polynomial X + 1 is encoded by 3 ("11" in binary).
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Formula
T(n,k) = the unique d such that A048720(d,k) = n, provided that such d exists, otherwise zero.
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