A280643 Numbers k such that k^3 has an odd number of digits and the middle digit is 3.
29, 34, 39, 46, 118, 125, 141, 142, 155, 161, 170, 211, 213, 477, 489, 511, 522, 526, 529, 535, 554, 573, 582, 586, 589, 631, 632, 633, 645, 663, 680, 691, 699, 723, 733, 744, 747, 770, 785, 790, 816, 817, 832, 854, 859, 863, 869, 873, 878, 892, 897, 901, 923
Offset: 1
Examples
29^3 = 24(3)89, 161^3 = 417(3)281, 663^3 = 2914(3)4247.
Links
- Lars Blomberg, Table of n, a(n) for n = 1..10000
- Jeremy Gardiner, Middle digit in cube numbers, Seqfan Mailing list, Dec 12 2016.
Crossrefs
Programs
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Mathematica
Select[Range[925],OddQ[len=Length[IntegerDigits[#^3]]]&&Part[IntegerDigits[#^3],(len+1)/2]==3 &] (* Stefano Spezia, Oct 03 2023 *)
Comments