A280647 Numbers k such that k^3 has an odd number of digits and the middle digit is 7.
31, 32, 105, 111, 128, 130, 149, 167, 173, 191, 192, 475, 483, 484, 491, 509, 524, 530, 534, 545, 546, 550, 556, 559, 584, 590, 592, 597, 614, 619, 624, 628, 637, 641, 665, 668, 692, 701, 725, 743, 750, 760, 781, 793, 809, 824, 836, 837, 843, 852, 861, 864
Offset: 1
Examples
31^3 = 29(7)91, 191^3 = 696(7)871, 619^3 = 2371(7)6659.
Links
- Lars Blomberg, Table of n, a(n) for n = 1..10000
- Jeremy Gardiner, Middle digit in cube numbers, Seqfan Mailing list, Dec 12 2016.
Crossrefs
Programs
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Mathematica
Select[Range[865], OddQ[len=Length[IntegerDigits[#^3]]]&&Part[IntegerDigits[#^3], (len+1)/2]==7 &] (* Stefano Spezia, Oct 03 2023 *)
Comments