A280700 Binary weight of terms of A005187: a(n) = A000120(A005187(n)).
0, 1, 2, 1, 3, 1, 2, 3, 4, 1, 2, 3, 3, 4, 3, 3, 5, 1, 2, 3, 3, 4, 3, 3, 4, 5, 3, 3, 4, 4, 3, 4, 6, 1, 2, 3, 3, 4, 3, 3, 4, 5, 3, 3, 4, 4, 3, 4, 5, 6, 3, 3, 4, 4, 3, 4, 5, 5, 3, 4, 4, 5, 6, 4, 7, 1, 2, 3, 3, 4, 3, 3, 4, 5, 3, 3, 4, 4, 3, 4, 5, 6, 3, 3, 4, 4, 3, 4, 5, 5, 3, 4, 4, 5, 6, 4, 6, 7, 3, 3, 4, 4, 3, 4, 5, 5, 3, 4, 4, 5, 6, 4, 6, 6, 3, 4, 4, 5, 6, 4, 5
Offset: 0
Keywords
Links
- Antti Karttunen, Table of n, a(n) for n = 0..8191
Programs
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Mathematica
Table[DigitCount[2 n - DigitCount[2 n, 2, 1], 2, 1], {n, 0, 120}] (* Michael De Vlieger, Mar 18 2017 *)
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PARI
b(n) = if(n<1, 0, b(n\2) + n%2); for(n=0, 150, print1(b(2*n - b(2*n)), ", ")) \\ Indranil Ghosh, Mar 21 2017
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Python
def A(n): return bin(2*n - bin(2*n)[2:].count("1"))[2:].count("1") print([A(n) for n in range(151)]) # Indranil Ghosh, Mar 21 2017
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Scheme
(define (A280700 n) (A000120 (A005187 n)))