A285173 Numbers n such that A002496(n+1) < A002496(n)^(1+1/n).

3, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 70

Offset: 1

Author

Felix Fröhlich, May 06 2017

Keywords

• nonn

Comments

Conjecture: The sequence is the complement of 1, 2, 4, 351 in A000027 (cf. Sun, 2013, Conjecture 2.6. (i)).

References

• Zhi-Wei Sun, Conjectures involving arithmetical sequences, in: Number Theory: Arithmetic in Shangri-La (eds., S. Kanemitsu, H. Li and J. Liu), Proceedings of the 6th China-Japan Seminar (Shanghai, August 15-17, 2011), World Scientific Publishing, Singapore, 2013, pp. 244-258.

Links

• Zhi-Wei Sun, Conjectures involving arithmetical sequences, arXiv:1208.2683 [math.CO], 2012.

Crossrefs

Cf. A000027, A002496.

Programs

PARI

a002496(n) = my(k=1, i=0); while(i < n, if(ispseudoprime(k^2+1), i++); if(i==n, return(k^2+1)); k++)
is(n) = a002496(n+1) < a002496(n)^(1+1/n)