A285337 a(n) = denominator of A065642(n)/n.
1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 2, 1, 1, 1, 1, 1, 3, 1, 1, 1, 1, 1, 2, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 3, 1, 1, 1, 4, 1, 1, 1, 1, 3, 1, 1, 8, 1, 5, 1, 1, 1, 3, 1, 4, 1, 1, 1, 2, 1, 1, 3, 1, 1, 1, 1, 1, 1, 1, 1, 3, 1, 1, 5, 1, 1, 1, 1, 4, 1, 1, 1, 2, 1, 1, 1, 1, 1, 3, 1, 1, 1, 1, 1, 8, 1, 7, 1, 5, 1, 1, 1, 1, 1, 1, 1, 3, 1, 1, 1, 4, 1, 1, 1, 1, 1, 1, 1, 4
Offset: 1
Links
- Antti Karttunen, Table of n, a(n) for n = 1..10000
Crossrefs
Programs
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Python
from sympy import primefactors, prod, Integer def a007947(n): return 1 if n<2 else prod(primefactors(n)) def a065642(n): if n==1: return 1 r=a007947(n) n += r while a007947(n)!=r: n+=r return n def a(n): return (a065642(n)/Integer(n)).denominator # Indranil Ghosh, Apr 20 2017
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Scheme
(define (A285337 n) (denominator (/ (A065642 n) n)))