A285712 a(1) = 0, and for n > 1, if n = 3k-1, then a(n) = k, otherwise a(n) = (A064216(n)+1)/2.
0, 1, 2, 3, 2, 4, 6, 3, 7, 9, 4, 10, 5, 5, 12, 15, 6, 8, 16, 7, 19, 21, 8, 22, 13, 9, 24, 11, 10, 27, 30, 11, 17, 31, 12, 34, 36, 13, 18, 37, 14, 40, 20, 15, 42, 28, 16, 26, 45, 17, 49, 51, 18, 52, 54, 19, 55, 29, 20, 33, 25, 21, 14, 57, 22, 64, 43, 23, 66, 69, 24, 39, 35, 25, 70, 75, 26, 44, 76, 27, 48, 79, 28, 82, 61, 29, 84, 23, 30, 87, 90, 31, 47, 46, 32
Offset: 1
Keywords
Links
- Antti Karttunen, Table of n, a(n) for n = 1..8192
Programs
-
Mathematica
a[n_] := a[n] = Which[n == 1, 0, Mod[n, 3] == 2, Ceiling[n/3], True, (Times @@ Power[If[# == 1, 1, NextPrime[#, -1]] & /@ First@ #, Last@ #] &@ Transpose@ FactorInteger[2 n - 1] + 1)/2]; Array[a, 95] (* Michael De Vlieger, Sep 22 2017 *)
-
Scheme
(define (A285712 n) (cond ((<= n 1) (- n 1)) ((= 2 (modulo n 3)) (A002264 (+ 1 n))) (else (/ (+ 1 (A064216 n)) 2))))
Formula
a(1) = 0, and for n > 1, if n = 3*k-1, then a(n) = k, otherwise a(n) = (A064216(n)+1)/2.
a(n) = (n+1)/3 + (3*A064216(n) - 2*n + 1)*( (n+1)^2 mod 3 )/6, for n>1. - Ammar Khatab, Sep 21 2020
Comments