A286255 Compound filter: a(n) = P(A046523(n), A046523(1+n)), where P(n,k) is sequence A000027 used as a pairing function.

2, 5, 12, 14, 23, 27, 38, 63, 40, 27, 80, 90, 23, 61, 216, 152, 80, 90, 80, 148, 61, 27, 302, 375, 40, 84, 179, 90, 467, 495, 530, 698, 61, 61, 826, 702, 23, 61, 412, 324, 467, 495, 80, 265, 148, 27, 1178, 1323, 109, 148, 142, 90, 302, 430, 412, 430, 61, 27, 1832, 1890, 23, 142, 2787, 2410, 601, 495, 80, 148, 601, 495, 2630, 2700, 23, 142, 265, 148, 601, 495, 1178

Offset: 1

Author

Antti Karttunen, May 07 2017

Keywords

• nonn

Links

• Antti Karttunen, Table of n, a(n) for n = 1..10000
• MathWorld, Pairing Function

Crossrefs

Cf. A000027, A046523, A286240, A286256, A286257, A286258.

Cf. A005383 (after its initial term 3, gives the positions of 23's in this sequence).

Cf. A051950 (one of the matches not matched by A046523 alone).

Programs

PARI

A046523(n) = { my(f=vecsort(factor(n)[, 2], , 4), p); prod(i=1, #f, (p=nextprime(p+1))^f[i]); };  \\ This function from Charles R Greathouse IV, Aug 17 2011
A286255(n) = (2 + ((A046523(n)+A046523(1+n))^2) - A046523(n) - 3*A046523(1+n))/2;
for(n=1, 10000, write("b286255.txt", n, " ", A286255(n)));

Python

from sympy import factorint
def T(n, m): return ((n + m)**2 - n - 3*m + 2)/2
def P(n):
    f = factorint(n)
    return sorted([f[i] for i in f])
def a046523(n):
    x=1
    while True:
        if P(n) == P(x): return x
        else: x+=1
def a(n): return T(a046523(n), a046523(n + 1)) # Indranil Ghosh, May 07 2017

Scheme

(define (A286255 n) (* (/ 1 2) (+ (expt (+ (A046523 n) (A046523 (+ 1 n))) 2) (- (A046523 n)) (- (* 3 (A046523 (+ 1 n)))) 2)))

Formula

a(n) = (1/2)*(2 + ((A046523(n)+A046523(1+n))^2) - A046523(n) - 3*A046523(1+n)).