A286569 Restricted growth sequence transform of "Hofstadter chaotic heart", A284019 (= A004001(n) - A005185(n)).

1, 1, 1, 2, 1, 1, 2, 2, 2, 1, 3, 2, 1, 1, 4, 2, 2, 2, 1, 1, 1, 3, 5, 4, 3, 3, 2, 1, 1, 1, 6, 2, 1, 4, 4, 3, 3, 2, 3, 3, 3, 3, 3, 5, 5, 7, 7, 8, 9, 9, 2, 5, 9, 1, 3, 7, 2, 3, 1, 1, 1, 1, 10, 2, 5, 6, 1, 7, 4, 4, 3, 3, 1, 5, 5, 7, 3, 9, 9, 5, 5, 9, 9, 5, 9, 7, 5, 7, 11, 7, 9, 11, 11, 12, 12, 13, 14, 9, 5, 3, 15, 7, 9, 16, 4, 12, 11, 5, 1, 16, 3, 3, 17, 1, 6, 18

Offset: 1

Author

Antti Karttunen, May 18 2017

Keywords

• nonn

Examples

			We start by setting a(1) = 1 for A284019(1) = 0. Then after, whenever A284019(k) is equal to some A284019(m) with m < k, we set a(k) = a(m). Otherwise (when the value is a new one, not encountered before), we allot for a(k) the least natural number not present among a(1) .. a(k-1).
For n=2, as A284019(2) = 0, which was already present at A284019(1), we set a(2) = a(1) = 1.
For n=3, as A284019(3) = 0, which was already present at n=1, we set a(3) = a(1) = 1.
For n=4, as A284019(4) = -1, which is a new value not encountered before, we set a(4) = 1 + max(a(1),a(2),a(3)) = 2.
For n=5, as A284019(5) = 0, which was already present at n=1, we set a(5) = a(1) = 1.
For n=7, as A284019(7) = -1, which was already present at n=4, we set a(7) = a(4) = 2.
For n=11, as A284019(11) = 1, which is a new value not encountered before (sign matters here), we set a(11) = 1 + max(a(1),..,a(10)) = 3.
		

Links

• Antti Karttunen, Table of n, a(n) for n = 1..47000

Crossrefs

Cf. A004001, A005185, A284019, A286560.