A290842 Numbers k such that the sum of digits of k^3 is 3^3 = 27.

27, 33, 36, 39, 42, 54, 57, 69, 72, 75, 78, 84, 87, 93, 105, 108, 111, 114, 135, 138, 147, 162, 165, 168, 174, 177, 219, 222, 225, 228, 231, 234, 258, 267, 270, 273, 276, 285, 291, 294, 312, 318, 321, 330, 342, 345, 348, 351, 360, 369, 381, 384, 390, 405, 417

Offset: 1

Author

Seiichi Manyama, Aug 12 2017

Keywords

• nonn
• base

Comments

It is obvious that if k is in this sequence, then so is 10*k. Additionally, this sequence contains other infinite subsequences. For example, 10^(2*k) + 10^k + 1 is in this sequence for all k > 0. - Altug Alkan, Aug 12 2017

Examples

			27^3 = 19683, 1 + 9 + 6 + 8 + 3 = 27 = 3^3.
		

Links

• Seiichi Manyama, Table of n, a(n) for n = 1..500

Crossrefs

Numbers k such that sum of digits of k^3 is m^3: A107679 (m=2), this sequence (m=3), A290843 (m=4), A159462 (m=5), A159463 (m=6).

Cf. A067075.

Programs

PARI

isok(n) = sumdigits(n^3) == 27; \\ Altug Alkan, Aug 12 2017