A292957 Rectangular array by antidiagonals: T(n,m) = rank of n*(r+m) when all the numbers k*(r+h), where r = sqrt(3), k>=1, h>=0, are jointly ranked.
1, 2, 3, 4, 7, 6, 5, 11, 13, 10, 8, 16, 21, 20, 14, 9, 22, 30, 32, 27, 18, 12, 26, 38, 44, 42, 36, 24, 15, 33, 49, 58, 61, 55, 46, 29, 17, 40, 59, 72, 78, 77, 69, 54, 34, 19, 47, 70, 87, 98, 100, 95, 84, 64, 39, 23, 52, 80, 103, 117, 124, 123, 113, 97, 73
Offset: 1
Examples
Northwest corner: 1 2 4 5 8 9 12 15 3 7 11 16 22 26 33 40 6 13 21 30 38 49 59 70 10 20 32 44 58 72 87 103 14 27 42 61 78 98 117 137 18 36 55 77 100 124 147 175 24 46 69 95 123 152 183 212 The numbers k*(r+h), approximately: (for k=1): 1.732 2.732 3.732 ... (for k=2): 3.464 5.464 7.464 ... (for k=3): 5.196 8.196 12.296 ... Replacing each by its rank gives 1 2 4 3 7 11 6 13 21
Links
- Clark Kimberling, Antidiagonals n=1..60, flattened
Programs
Formula
T(n,m) = Sum_{k=1...[n + m*n/r]} [1 - r + n*(r + m)/k], where r=sqrt(3) and [ ]=floor.
Comments