A292961 Rectangular array by antidiagonals: T(n,m) = rank of n*(r+m) when all the numbers k*(r+h), where r = -1+(1+sqrt(5))/2, k>=1, h>=0, are jointly ranked.
1, 3, 2, 6, 8, 4, 9, 15, 13, 5, 12, 22, 25, 19, 7, 17, 30, 38, 35, 27, 10, 20, 40, 52, 54, 48, 33, 11, 24, 49, 66, 74, 72, 61, 41, 14, 28, 58, 82, 93, 98, 91, 73, 46, 16, 32, 67, 96, 115, 124, 122, 108, 85, 55, 18, 37, 78, 111, 136, 151, 155, 146, 129, 101
Offset: 1
Examples
Northwest corner: 1 3 6 9 12 17 20 2 8 15 22 30 40 49 4 13 25 38 52 66 82 5 19 35 54 74 93 115 7 27 48 72 98 124 151 10 33 61 91 122 155 190 11 41 73 108 146 187 226 14 46 85 129 172 218 266 The numbers k*(r+h), approximately: (for k=1): 0.618 1.618 2.618 ... (for k=2): 1.236 3.236 5.236 ... (for k=3): 1.854 4.854 7.854 ... Replacing each k*(r+h) by its rank gives 1 3 6 2 8 15 4 13 25
Links
- Clark Kimberling, Antidiagonals n=1..60, flattened
Programs
Formula
T(n,m) = Sum_{k=1...[n + m*n/r]} [1 - r + n*(r + m)/k], where r=1/GoldenRatio and [ ]=floor.
Comments