cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A293645 Positive numbers that are the sum of two (possibly negative) coprime cubes.

Original entry on oeis.org

1, 2, 7, 9, 19, 26, 28, 35, 37, 61, 63, 65, 91, 98, 117, 124, 126, 127, 133, 152, 169, 189, 215, 217, 218, 271, 279, 316, 331, 335, 341, 342, 344, 351, 370, 386, 387, 397, 407, 468, 469, 485, 511, 513, 539, 547, 559, 602, 604, 631, 637, 657, 665, 721, 728, 730
Offset: 1

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Author

Rosalie Fay, Oct 16 2017

Keywords

Comments

Also sum or difference of two coprime cubes. - David A. Corneth, Oct 20 2017

Examples

			19 = 3^3 + (-2)^3, where 3 and -2 are coprime, so 19 is in the sequence.
152 = 5^3 + 3^3, where 5 and 3 are coprime, so 152 is in the sequence.
		

Crossrefs

Cf. A003325 (positive cubes); A020895 (cubefree); A293646 (only coprime); A293647, A293650.

Programs

  • Maple
    filter:= proc(n) local s,x,y;
      for s in numtheory:-divisors(n) do
        x:= s/2 + sqrt(12*n/s-3*s^2)/6;
        if not x::integer then next fi;
        y:= s - x;
        if igcd(x,y) = 1 then return true fi;
      od;
      false
    end proc:
    select(filter, [seq(seq(9*i+j,j=[1,2,7,8,9]),i=0..1000)]); # Robert Israel, Oct 22 2017
  • Mathematica
    smax = 100000; (* upper limit for last term *)
    m0 = smax^(1/3) // Ceiling;
    f[m_] := f[m] = Module[{c, s, d}, Table[c = CoprimeQ[i^3, j^3]; {s = i^3 + j^3; If[0 < s <= smax && c, s, Nothing], d = j^3 - i^3; If[0 < d <= smax && c, d, Nothing]}, {i, 0, m}, {j, i, m}] // Flatten // Union];
    f[m = m0];
    f[m += m0];
    While[f[m] != f[m - m0], m += m0];
    f[m] (* Jean-François Alcover, Jun 28 2023 *)
  • PARI
    upto(lim) = {my(res = List([2]), c, i, j); for(i=1,sqrtnint(lim, 3), for(j=0, sqrtnint(lim - i^3, 3), if(gcd(i, j) == 1, listput(res, c)))); for(i=1, sqrtint(lim\3)+1, for(j = 1, i, if(gcd(i, j) == 1, c = i^3 - (i-j)^3; if(c<=lim, listput(res, c), next(2))))); listsort(res, 1); res} \\ David A. Corneth, Oct 20 2017