A294880 Number of divisors of n that are in Perrin sequence, A001608.
0, 1, 1, 1, 1, 2, 1, 1, 1, 3, 0, 3, 0, 2, 2, 1, 1, 2, 0, 3, 2, 2, 0, 3, 1, 1, 1, 2, 1, 4, 0, 1, 1, 2, 2, 3, 0, 1, 2, 3, 0, 3, 0, 2, 2, 1, 0, 3, 1, 3, 3, 1, 0, 2, 1, 2, 1, 2, 0, 5, 0, 1, 2, 1, 1, 3, 0, 3, 1, 4, 0, 3, 0, 1, 2, 1, 1, 3, 0, 3, 1, 1, 0, 4, 2, 1, 2, 2, 0, 5, 1, 1, 1, 1, 1, 3, 0, 2, 1, 3, 0, 4, 0, 1, 3
Offset: 1
Keywords
Examples
For n = 22, with divisors [1, 2, 11, 22], both 2 and 22 are in A001608, thus a(22) = 2. For n = 644, with divisors [1, 2, 4, 7, 14, 23, 28, 46, 92, 161, 322, 644], 2, 7 and 644 are in A001608, thus a(644) = 3.
Links
- Antti Karttunen, Table of n, a(n) for n = 1..24914
Programs
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Mathematica
With[{s = LinearRecurrence[{0, 1, 1}, {3, 2, 5}, 15]}, Table[DivisorSum[n, 1 &, MemberQ[s, #] &], {n, 1, s[[-1]]}]] (* Amiram Eldar, Jan 01 2024 *)
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PARI
A001608(n) = if(n<0, 0, polsym(x^3-x-1, n)[n+1]); A294878(n) = { my(k=1,v); while((v=A001608(k))
A294880(n) = sumdiv(n,d,A294878(d));
Formula
a(n) = Sum_{d|n} A294878(d).
Asymptotic mean: Limit_{m->oo} (1/m) * Sum_{k=1..m} a(k) = -1/5 + Sum_{n>=3} 1/A001608(n) = 1.603595519775230150708... . - Amiram Eldar, Jan 01 2024