A295955 Solution of the complementary equation a(n) = a(n-1) + a(n-2) + b(n) + 1, where a(0) = 3, a(1) = 4, b(0) = 1, b(1) = 2, b(2) = 5, and (a(n)) and (b(n)) are increasing complementary sequences.
3, 4, 13, 24, 45, 78, 133, 222, 367, 602, 984, 1602, 2603, 4223, 6845, 11088, 17954, 29064, 47041, 76129, 123196, 199352, 322576, 521957, 844563, 1366551, 2211146, 3577730, 5788910, 9366675, 15155621, 24522333, 39677992, 64200364, 103878396, 168078801
Offset: 0
Examples
a(0) = 3, a(1) = 4, b(0) = 1, b(1) = 2, b(2) = 5 b(3) = 6 (least "new number") a(2) = a(1) + a(0) + b(2) + 1 = 13 Complement: (b(n)) = (1, 2, 5, 6, 7, 8, 9, 10, 11, 12, 14, 15, 16, 17, 18, ...)
Links
- Clark Kimberling, Table of n, a(n) for n = 0..2000
- Clark Kimberling, Complementary equations, J. Int. Seq. 19 (2007), 1-13.
Programs
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Mathematica
a[0] = 3; a[1] = 4; b[0] = 1; b[1] = 2; b[2] = 5; a[n_] := a[n] = a[n - 1] + a[n - 2] + b[n] + 1; j = 1; While[j < 6, k = a[j] - j - 1; While[k < a[j + 1] - j + 1, b[k] = j + k + 2; k++]; j++]; Table[a[n], {n, 0, k}]; (* A295955 *)
Extensions
Definition corrected by Georg Fischer, Sep 27 2020
Comments