A298848 Number of partitions of n^3 into distinct cubes > 1.

1, 0, 1, 1, 1, 1, 2, 1, 1, 1, 1, 1, 3, 2, 5, 4, 3, 4, 13, 11, 15, 20, 23, 34, 52, 49, 97, 118, 164, 192, 296, 330, 525, 745, 825, 1354, 1820, 1994, 3356, 4605, 5543, 8335, 12319, 13124, 21133, 28634, 33209, 51272, 71154, 85329, 126806, 174704, 210157, 310269, 433490, 511199

Offset: 0

Author

Ilya Gutkovskiy, Jan 27 2018

Keywords

• nonn

Examples

			a(6) = 2 because we have [216] and [125, 64, 27].
		

Links

• Index entries for sequences related to sums of cubes
• Index entries for related partition-counting sequences

Crossrefs

Cf. A000578, A003108, A030272, A078128, A259792, A279329, A280130, A298641, A298671, A298672.

Formula

a(n) = [x^(n^3)] Product_{k>=2} (1 + x^(k^3)).

a(n) = A280130(A000578(n)).