cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A299322 Ranks of {2,3}-power towers with neither consecutive 2's nor consecutive 3's; see Comments.

Original entry on oeis.org

1, 2, 4, 5, 10, 11, 22, 23, 45, 48, 92, 97, 185, 196, 372, 393, 745, 788, 1492, 1577, 2985, 3156, 5972, 6313, 11945, 12628, 23892, 25257, 47785, 50516, 95572, 101033, 191145, 202068, 382292, 404137, 764585, 808276, 1529172, 1616553, 3058345, 3233108, 6116692, 6466217
Offset: 1

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Author

Clark Kimberling, Feb 07 2018

Keywords

Comments

Suppose that S is a set of real numbers. An S-power-tower, t, is a number t = x(1)^x(2)^...^x(k), where k >= 1 and x(i) is in S for i = 1..k. We represent t by (x(1), x(2), ..., x(k)), which for k > 1 is defined as (x(1), (x(2), ..., x(k))); (2,3,2) means 2^9. The number k is the *height* of t. If every element of S exceeds 1 and all the power towers are ranked in increasing order, the position of each in the resulting sequence is its *rank*. See A299229 for a guide to related sequences.

Examples

			The first seven terms are the ranks of these towers: t(1) = (2), t(2) = (3), t(4) = (2,3), t(5) = (3,2), t(10) = (2,3,2), t(11) = (3,2,3), t(22) = (3,2,3,2).
		

Crossrefs

Cf. A299229.

Programs

  • Mathematica
    t[1] = {2}; t[2] = {3}; t[3] = {2, 2}; t[4] = {2, 3}; t[5] = {3, 2};
    t[6] = {2, 2, 2}; t[7] = {3, 3}; t[8] = {3, 2, 2}; t[9] = {2, 2, 3};
    t[10] = {2, 3, 2}; t[11] = {3, 2, 3}; t[12] = {3, 3, 2};
    z = 190; g[k_] := If[EvenQ[k], {2}, {3}]; f = 6;
    While[f < 13, n = f; While[n < z, p = 1;
      While[p < 12, m = 2 n + 1; v = t[n]; k = 0;
        While[k < 2^p, t[m + k] = Join[g[k], t[n + Floor[k/2]]]; k = k + 1];
       p = p + 1; n = m]]; f = f + 1]
    Select[Range[5000], Max[Map[Length, Split[t[#]]]] < 2 &]

Formula

Conjectures from Colin Barker, Feb 09 2018: (Start)
G.f.: x*(1 + x + x^2 + x^4 - 2*x^5 + 2*x^6 - 2*x^7 + x^8) / ((1 - x)*(1 + x^2)*(1 - 2*x^2)).
a(n) = a(n-1) + a(n-2) - a(n-3) + 2*a(n-4) - 2*a(n-5) for n >= 10.
(End)

Extensions

a(37)-a(44) from Pontus von Brömssen, Aug 08 2024